我试图检索分页列表和总数“关于属于特定用户的”案例“的”通知“。在JOERE中使用OR缓慢JOIN查询 - 缺少可能的索引?
通知有几个条件为“未锁定”,“不是私人”,“尚未见过”,应该返回#找到,然后按照创建的日期降序排列。
最后一个条件是,该通知不是由用户本身产生,或该通知的类型是“行为”(枚举)和user_id是在通知中涉及“REF_ID”
此查询正在接近5秒钟,以对最近的变化中的200k行和在cases
和50个用户中少于4k行进行运行。
+-----+
| cnt |
+-----+
| 13 |
+-----+
1 row in set (4.67 sec)
该查询是否可以自行优化,还是需要重构?
SELECT count(*) as cnt
FROM recent_changes rc
LEFT JOIN `case` c on c.id = rc.case_id
LEFT JOIN `user` u on u.id = rc.user_id
WHERE
(
rc.user_id != c.user_id AND c.user_id = '25'
OR
(rc.type = 'conduct' AND rc.ref_id = '25')
)
AND c.locked = 'N' AND rc.private != 'Y'
AND seen = 'false'
ORDER BY rc.datecreated DESC;
Explain输出上recent_changes
+----+-------------+-------+--------+--------------------------+-------------------------+---------+--------------------------+------+------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+--------------------------+-------------------------+---------+--------------------------+------+------------------------------+
| 1 | SIMPLE | c | ALL | PRIMARY,user_user_id_idx | NULL | NULL | NULL | 3699 | Using where; Using temporary |
| 1 | SIMPLE | rc | ref | idx_recent_changes_case | idx_recent_changes_case | 5 | xxxxxxxxxxxxx.c.id | 25 | Using where |
| 1 | SIMPLE | u | eq_ref | PRIMARY | PRIMARY | 4 | xxxxxxxxxxxxx.rc.user_id | 1 | Using index |
+----+-------------+-------+--------+--------------------------+-------------------------+---------+--------------------------+------+------------------------------+
指数:上case
表
+----------------+------------+------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+----------------+------------+------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
| recent_changes | 0 | PRIMARY | 1 | id | A | 182807 | NULL | NULL | | BTREE | |
| recent_changes | 1 | recent_changes_user_id_idx | 1 | user_id | A | 96 | NULL | NULL | YES | BTREE | |
| recent_changes | 1 | idx_recent_changes_user_case | 1 | user_id | A | 92 | NULL | NULL | YES | BTREE | |
| recent_changes | 1 | idx_recent_changes_user_case | 2 | case_id | A | 18280 | NULL | NULL | YES | BTREE | |
| recent_changes | 1 | idx_recent_changes_case | 1 | case_id | A | 7312 | NULL | NULL | YES | BTREE | |
+----------------+------------+------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+
指标:
+-------+------------+------------------+--------------+---------------------+-----------+-------------+----------+--------+------+------------+---------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+-------+------------+------------------+--------------+---------------------+-----------+-------------+----------+--------+------+------------+---------+
| case | 0 | PRIMARY | 1 | id | A | 3753 | NULL | NULL | | BTREE | |
| case | 1 | id_idx | 1 | member_id | A | 3753 | NULL | NULL | YES | BTREE | |
| case | 1 | user_user_id_idx | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | |
| case | 1 | case_ha_id | 1 | health_authority_id | A | 28 | NULL | NULL | YES | BTREE | |
+-------+------------+------------------+--------------+---------------------+-----------+-------------+----------+--------+------+------------+---------+
它做以下概念:
在recent_changes查找最近的行,其中:
i)本recent_changes行通过由该电流的user_id II拥有CASE_ID加入到case
表)和recent_changes行不是由当前USER_ID创建
OR
i)所述recent_changes行是 “行为” 类型的,并且当前的user_id是在recent_changes.ref_id柱
如果删除了“OR( rc.type ='conduct'AND rc.ref_id ='25')“condition,那么我得到1秒钟的响应时间。
如果我删除“rc.user_id!= c.user_id AND c.user_id ='25'或”条件,它仍然需要大约5秒才能完成。
编辑
改变连接顺序剃掉1/2秒,虽然我不能在rc
.case_id加入case
直到我加入rc
第一:未知列“rc.user_id '在'where子句'中。
新建查询:
SELECT count(*) as cnt
FROM `user` u
LEFT JOIN `recent_changes` rc on u.id = rc.user_id
LEFT JOIN `case` c on c.id = rc.case_id
WHERE
(
rc.user_id != c.user_id AND c.user_id = '25'
OR
(rc.type = 'conduct' AND rc.ref_id = '25')
)
AND c.locked = 'N' AND rc.private != 'Y'
AND seen = 'false'
ORDER BY rc.datecreated DESC;
取出“ORDER BY”条款似乎并没有增加新的连接顺序查询,虽然我现在是更好地了解它的性能影响。
使用UNION没有任何速度快,但运行的每个单独选择已指出,首只选择需要.3s其中第二选择是在4S:
select count(*) as cnt
FROM (
SELECT count(*) FROM `user` u
LEFT JOIN `recent_changes` rc on u.id = rc.user_id
LEFT JOIN `case` c on c.id = rc.case_id
WHERE rc.user_id != c.user_id AND c.user_id = '25'
AND c.locked = 'N' AND rc.private != 'Y'
AND seen = 'false'
UNION ALL
SELECT count(*) as cnt
FROM `user` u
LEFT JOIN `recent_changes` rc on u.id = rc.user_id
LEFT JOIN `case` c on c.id = rc.case_id
WHERE rc.type = 'conduct' AND rc.ref_id = '25'
AND c.locked = 'N' AND rc.private != 'Y'
AND seen = 'false') x
我相信recent_changes rc
表没有按“T有必要的索引作为每说明:
EXPLAIN SELECT count(*) FROM `user` u LEFT JOIN `recent_changes` rc on u.id = rc.user_id LEFT JOIN `case` c on c.id = rc.case_id WHERE rc.user_id != c.user_id AND c.user_id = '25' AND c.locked = 'N' AND rc.private != 'Y' AND seen = 'false';
在奔跑,5S <
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
| 1 | SIMPLE | c | ref | PRIMARY,user_user_id_idx | user_user_id_idx | 5 | const | 383 | Using where |
| 1 | SIMPLE | rc | ref | recent_changes_user_id_idx,idx_recent_changes_user_case,idx_recent_changes_case | idx_recent_changes_case | 5 | hsaedmp_jason.c.id | 20 | Using where |
| 1 | SIMPLE | u | eq_ref | PRIMARY | PRIMARY | 4 | hsaedmp_jason.rc.user_id | 1 | Using index |
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
在奔跑> 4S
EXPLAIN SELECT count(*) as cnt FROM `user` u LEFT JOIN `recent_changes` rc on u.id = rc.user_id LEFT JOIN `case` c on c.id = rc.case_id WHERE rc.type = 'conduct' AND rc.ref_id = '25' AND c.locked = 'N' AND rc.private != 'Y' AND seen = 'false';
密钥= NULL这是不好的。
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
| 1 | SIMPLE | c | ALL | PRIMARY | NULL | NULL | NULL | 3797 | Using where |
| 1 | SIMPLE | rc | ref | recent_changes_user_id_idx,idx_recent_changes_user_case,idx_recent_changes_case | idx_recent_changes_case | 5 | hsaedmp_jason.c.id | 20 | Using where |
| 1 | SIMPLE | u | eq_ref | PRIMARY | PRIMARY | 4 | hsaedmp_jason.rc.user_id | 1 | Using index |
+----+-------------+-------+--------+---------------------------------------------------------------------------------+-------------------------+---------+--------------------------+------+-------------+
我感到困惑的是,解释说,case
表不使用钥匙节目,但现在看来,该recent_changes
表是需要对ref_id
列的索引的一个?
下面是该索引的解释,在这里看起来好多了,但我还没有能够在产品上测试它。
+----+-------------+-------+------------+--------+----------------------------------------------------------------------------------------------------------------------------------
---+------------------------+---------+--------------------------+------+----------+-------------+
| id | select_type | table | partitions | type | possible_keys
| key | key_len | ref | rows | filtered | Extra |
+----+-------------+-------+------------+--------+----------------------------------------------------------------------------------------------------------------------------------
---+------------------------+---------+--------------------------+------+----------+-------------+
| 1 | SIMPLE | rc | NULL | ref | recent_changes_user_id_idx,idx_recent_changes_user_case,idx_recent_changes_case,idx_recent_changes_case_date,idx_recent_changes_r
ef | idx_recent_changes_ref | 5 | const | 2096 | 3.12 | Using where |
| 1 | SIMPLE | u | NULL | eq_ref | PRIMARY
| PRIMARY | 4 | hsaedmp_jason.rc.user_id | 1 | 100.00 | Using index |
| 1 | SIMPLE | c | NULL | eq_ref | PRIMARY
| PRIMARY | 4 | hsaedmp_jason.rc.case_id | 1 | 50.00 | Using where |
+----+-------------+-------+------------+--------+----------------------------------------------------------------------------------------------------------------------------------
---+------------------------+---------+--------------------------+------+----------+-------------+
UPDATE
我已经返工使用UNION语句的查询,改变连接顺序和由上recent_changes
表添加化合物索引一起带来的查询响应时间< 10ms的。
这是使用UNION语句的新查询。
select count(*) as num
FROM (
(
SELECT rc1.*
FROM `user` u1
LEFT JOIN `recent_changes` rc1 on u1.id = rc1.user_id
LEFT JOIN `case` c1 on c1.id = rc1.case_id
WHERE
(rc1.user_id != c1.user_id AND c1.user_id = '1')
AND c1.locked = 'Y'
AND rc1.private != 'Y'
AND seen = 'false'
ORDER BY rc1.datecreated DESC
)
UNION
(
SELECT rc.*
FROM `user` u
LEFT JOIN `recent_changes` rc on u.id = rc.user_id
LEFT JOIN `case` c on c.id = rc.case_id
WHERE
(rc.type = 'conduct' AND rc.ref_id = '1')
AND c.locked = 'Y'
AND rc.private != 'Y'
AND seen = 'false'
ORDER BY rc.datecreated DESC
)
) x;
而我根据最终查询创建的索引是我需要的。
ALTER TABLE recent_changes ADD INDEX idx_recent_changes_notification (type, ref_id, private, seen, user_id);
感谢大家的意见!
'OR'是MySQL中的一个性能杀手。试着将它分成两个查询,你可以结合'UNION'。 – Barmar
另外,运行EXPLAIN EXTENDED,然后显示SHOW WARNINGS。它会揭示一些关于MySQL如何解释你的JOIN的有用信息 – Strawberry
尝试在'recent_changes(type,ref_id,private,user_id)上创建一个复合索引'这是一个所谓的复合覆盖索引,并且有助于加速UNION的第二部分。请[编辑]你的问题,让我们知道它是否有帮助。尝试修复性能问题时,在表中放置大量单列索引通常是有害的。 –