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我使用代码来创建一个图像与PHP GD需要一个完全透明的背景。当我创建它时,它在浏览器中显示正常,但在我的iPhone应用程序中显示错误。我不知道为什么,但在我的iPhone中,它显示黑色的所有透明度。这似乎是一个GD问题,因为当我将我的GD映像加载到Web编辑器并重新导出它时,它在我的iPhone应用程序中显示得很好。是否有一种特殊的方式,我应该从GD或其他东西导出PNG图像,或者这是一种错误?这里是代码:PHP的GD透明不适用于iPhone
$filename = "./me.jpg";
$image_s = imagecreatefromjpeg($filename);
list($current_width, $current_height) = getimagesize($filename);
$left = isset($_GET['pl']) ? abs($_GET['pl']) : 0;
$top = isset($_GET['pt']) ? abs($_GET['pt']) : 0;
$width = isset($_GET['cs']) ? abs($_GET['cs']) : 65;
$height = isset($_GET['cs']) ? abs($_GET['cs']) : 65;
$canvas = imagecreatetruecolor($width, $height);
$current_image = imagecreatefromjpeg($filename);
imagecopy($canvas, $current_image, 0, 0, $left, $top, $current_width, $current_height);
$newwidth = 65;
$newheight = 65;
$image = imagecreatetruecolor($newwidth, $newheight);
imagealphablending($image, true);
imagecopyresampled($image, $canvas, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
$mask = imagecreatetruecolor($newwidth, $newheight);
$transparent = imagecolorallocate($mask, 255, 255, 255);
imagecolortransparent($mask, $transparent);
imagefilledellipse($mask, $newwidth/2, $newheight/2, $newwidth, $newheight, $transparent);
$red = imagecolorallocate($mask, 0, 0, 0);
imagecopymerge($image, $mask, 0, 0, 0, 0, $newwidth + 10, $newheight + 10, 100);
imagecolortransparent($image, $red);
imagefill($image,0,0, $red);
header('Content-type: image/png');
imagepng($image);
imagedestroy($image);
imagedestroy($mask);