不能提取正则表达式的子字符串

Question

我想为git写一个prepare-commit-msg钩子。该脚本应该做以下步骤：

1. 获取当前的git分支名（工作）
2. 提取issue-id（不工作）
3. 检查是否issue-id已经在提交味精
4. 如果没有插入[issue-id]提交信息前

的issue-id了这种模式[a-zA-Z]+-\d+和分支的名称应该是舒美特像feature/issue-id-my-small-description一样兴奋。

但现在，提取的部分是不正常...

这是我准备提交 - 味精脚本：

# Regex used to extract the issue id 
REGEX_ISSUE_ID="s/([a-zA-Z]+-\d+)//" 

# Find current branch name 
BRANCH_NAME=$(git symbolic-ref --short HEAD) 

# Extract issue id from branch name 
ISSUE_ID= $BRANCH_NAME | sed -r $REGEX_ISSUE_ID 

# Check if the issue id is already in the msg 
ISSUE_IN_COMMIT=$(grep -c "\[$ISSUE_ID\]" $1) 

# Check if branch name is not null and if the issue id is already in the commit msg 
if [ -n "$BRANCH_NAME" ] && ! [[ $ISSUE_IN_COMMIT -ge 1 ]]; then 
    # Prefix with the issue id surrounded with brackets 
    sed -i.bak -e "1s/^/[$ISSUE_ID] /" $1 
fi 

编辑添加输入/输出例如

输入$1是git commit消息，类似于

fix bug on login 

或

fix MyIssue-234 which is a bug on login 

输出应该是这个问题的ID即输入：

[MyIssue-123] fix bug on login 

Answer 1

我不知道什么以及为什么这样做，你做什么，但是这是最接近我通过固定我的想法得到了在你的代码加以纠正：

# Regex used to extract the issue id 
REGEX_ISSUE_ID="s/\[([a-zA-Z]+-[0-9]+)\].*/\1/" 

# Find current branch name 
BRANCH_NAME=$(git symbolic-ref --short HEAD) 
if [[ -z "$BRANCH_NAME" ]]; then 
    echo "No brach name... "; exit 1 
fi 

# Extract issue id from branch name 
ISSUE_ID=$(echo "$BRANCH_NAME" | sed -r "$REGEX_ISSUE_ID") 

# Check if the issue id is already in the msg 
ISSUE_IN_COMMIT=$(echo "$@" | grep -c "^\[*$ISSUE_ID\]*") 

# Check if branch name is not null and if the issue id is already in the commit msg 
if [[ -n "$BRANCH_NAME" ]]; then 
    if [[ $ISSUE_IN_COMMIT -gt 0 ]]; then 
     shift # Drop the issue if from the msg 
    fi 
    # Prefix with the issue id surrounded with brackets 
    MESSAGE="[$ISSUE_ID] $@" 
fi 

echo "$MESSAGE" 

其中$@是所有你之后“修理”（如提供的话。 "$@" = "bug" "on" "login"）。其余的我希望你在把它与你的原始代码进行比较后能够理解。