0
我看到了一个获取接口的mac和ipv4地址的示例代码。我改了一点试图让该接口,但该方案的IPv6地址失败说“27:13:错误:分配给从类型类型‘u_int32_t’时,不兼容的类型“结构libnet_in6_addr”如何使用libnet获取接口的ipv6地址?
#include <stdlib.h>
#include <libnet.h>
#include <stdint.h>
int main() {
libnet_t *l; /* libnet context */
char errbuf[LIBNET_ERRBUF_SIZE];
u_int32_t ip_addr;
struct libnet_ether_addr *mac_addr;
l = libnet_init(LIBNET_RAW4, NULL, errbuf);
if (l == NULL) {
fprintf(stderr, "libnet_init() failed: %s\n", errbuf);
exit(EXIT_FAILURE);
}
ip_addr = libnet_get_ipaddr4(l);
if (ip_addr != -1)
printf("IP address: %s\n", libnet_addr2name4(ip_addr,\
LIBNET_DONT_RESOLVE));
else
fprintf(stderr, "Couldn't get own IP address: %s\n",\
libnet_geterror(l));
u_int32_t ipv6_addr;
ipv6_addr = libnet_get_ipaddr6(l);
if (ip_addr != -1)
printf("IPv6 address: %s\n", libnet_addr2name6(ip_addr,\
LIBNET_DONT_RESOLVE));
else
fprintf(stderr, "Couldn't get own IPv6 address: %s\n",\
libnet_geterror(l));
mac_addr = libnet_get_hwaddr(l);
if (mac_addr != NULL)
printf("MAC address: %02X:%02X:%02X:%02X:%02X:%02X\n",\
mac_addr->ether_addr_octet[0],\
mac_addr->ether_addr_octet[1],\
mac_addr->ether_addr_octet[2],\
mac_addr->ether_addr_octet[3],\
mac_addr->ether_addr_octet[4],\
mac_addr->ether_addr_octet[5]);
else
fprintf(stderr, "Couldn't get own MAC address: %s\n",\
libnet_geterror(l));
libnet_destroy(l);
return 0;
}
我不不知道用什么来存储ipv6地址,所以我使用u_int32_t,我试过u_int64_t它不起作用。我想知道如果再次遇到这样的基本问题,我应该在哪里找到解决方案。我找不到有关ipv6地址的示例。