有人可以解释在下面的lambda函数中创建线程的位置吗? 使用什么技术? 有人可以推荐一个参考来理解语义吗?使用lambda表达式构建线程
我现在张贴的全码:
class ThreadPool {
public:
ThreadPool(size_t);
template<class F, class... Args>
auto enqueue(F&& f, Args&&... args)
->std::future<typename std::result_of<F(Args...)>::type>;
~ThreadPool();
private:
// need to keep track of threads so we can join them
std::vector<std::thread> workers_m;
// the task queue
std::queue< std::function<void()> > tasks_m;
// synchronization
std::mutex queue_mutex_m;
std::condition_variable condition_m;
bool stop_m;
};
// the constructor just launches some amount of workers
inline ThreadPool::ThreadPool(size_t threads)
: stop_m(false)
{
std::thread::id id = std::this_thread::get_id();
for (size_t i = 0; i < threads; ++i)
{
workers_m.emplace_back(
[this]
{
for (;;)
{
std::function<void()> task;
{
std::unique_lock<std::mutex> lock(this- >queue_mutex_m);
std::thread::id id1 = std::this_thread::get_id();
this->condition_m.wait(lock, [this]{ return this->stop_m || !this->tasks_m.empty(); });
std::thread::id id = std::this_thread::get_id();
if (this->stop_m && this->tasks_m.empty())
return;
task = std::move(this->tasks_m.front());
this->tasks_m.pop();
}
task();
}
}
);
}
}
您没有在任何地方创建线程。 –
感谢T.C.,我现在添加了完整的代码 – user2286810
'emplace_back'函数被赋予了一个lambda,它在'workers_m'向量上构造了一个'std :: thread'。 – Alejandro