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我正在尝试在设置了两个文本字段的表单中创建一个下拉框。但是，当我尝试将下拉列表添加到表单时，它会更改结束值，即使我没有更改类型或答案，它也会更改它返回的值。原代码我写的，通过完美的运行是：Exchange PowerShell下拉问题
function button ($title,$mailbx, $WF, $TF) {
###################Load Assembly for creating form & button######
[void][System.Reflection.Assembly]::LoadWithPartialName(“System.Windows.Forms”)
[void][System.Reflection.Assembly]::LoadWithPartialName(“Microsoft.VisualBasic”)
#####Define the form size & placement
$form = New-Object “System.Windows.Forms.Form”;
$form.Width = 750;
$form.Height = 500;
$form.Text = $title;
$form.StartPosition = [System.Windows.Forms.FormStartPosition]::CenterScreen;
##############Define text label1
$textLabel1 = New-Object “System.Windows.Forms.Label”;
$textLabel1.Left = 25;
$textLabel1.Top = 15;
$textLabel1.Text = $mailbx;
##############Define text label2
$textLabel2 = New-Object “System.Windows.Forms.Label”;
$textLabel2.Left = 25;
$textLabel2.Top = 50;
$textLabel2.Text = $WF;
##############Define text label3
$textLabel3 = New-Object “System.Windows.Forms.Label”;
$textLabel3.Left = 25;
$textLabel3.Top = 85;
$textLabel3.Text = $TF;
############Define text box1 for input
$textBox1 = New-Object “System.Windows.Forms.TextBox”;
$textBox1.Left = 150;
$textBox1.Top = 10;
$textBox1.width = 200;
############Define text box2 for input
$textBox2 = New-Object “System.Windows.Forms.TextBox”;
$textBox2.Left = 150;
$textBox2.Top = 50;
$textBox2.width = 200;
############Define text box3 for input
$textBox3 = New-Object “System.Windows.Forms.TextBox”;
$textBox3.Left = 150;
$textBox3.Top = 90;
$textBox3.width = 200;
#############Define default values for the input boxes
$defaultValue = “”
$textBox1.Text = $defaultValue;
$textBox2.Text = $defaultValue;
$textBox3.Text = $defaultValue;
#############define OK button
$button = New-Object “System.Windows.Forms.Button”;
$button.Left = 360;
$button.Top = 85;
$button.Width = 100;
$button.Text = “Ok”;
############# This is when you have to close the form after getting values
$eventHandler = [System.EventHandler]{
$textBox1.Text;
$textBox2.Text;
$textBox3.Text;
$form.Close();};
$button.Add_Click($eventHandler) ;
#############Add controls to all the above objects defined
$form.Controls.Add($button);
$form.Controls.Add($textLabel1);
$form.Controls.Add($textLabel2);
$form.Controls.Add($textLabel3);
$form.Controls.Add($textBox1);
$form.Controls.Add($textBox2);
$form.Controls.Add($textBox3);
$ret = $form.ShowDialog();
#################return values
return $textBox1.Text, $textBox2.Text, $textBox3.Text
}
$return= button “Enter Info” “First Name” “Last Name” “Email Address”
$return2 = ($return[0] + " " + $return[1])
$return3 = ($return[0] + "." + $return[1])
$return4 = $return[0] + "." + $return[1] + "$return[2]"
New-Mailbox -Alias $return3 -Name $return2 -FirstName $return[0] -LastName $return[1] -UserPrincipalName $return4 -Password (ConvertTo-SecureString -String '[email protected]' -AsPlainText -Force) -ResetPasswordOnNextLogon $true
Set-User -Identity $return3 -StreetAddress '1600 Pennsylvania Ave NW' -City 'Washington' -StateOrProvince 'D.C.' -PostalCode '20500' -Phone '202-456-1111' -Fax '202-456-2461'
下拉代码我是
########################
# Edit This item to change the DropDown Values
[array]$DropDownArray = "@yahoo.com", "@gmail.com", "@lewisJ.com"
# This Function Returns the Selected Value and Closes the Form
function Return-DropDown {
$Choice = $DropDown.SelectedItem.ToString()
}
[System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
[System.Reflection.Assembly]::LoadWithPartialName("System.Drawing")
$DropDown = new-object System.Windows.Forms.ComboBox
$DropDown.Location = new-object System.Drawing.Size(400,10)
$DropDown.Size = new-object System.Drawing.Size(130,30)
ForEach ($Item in $DropDownArray) {
$DropDown.Items.Add($Item)
}
$Form.Controls.Add($DropDown)
$DropDownLabel = new-object System.Windows.Forms.Label
$DropDownLabel.Location = new-object System.Drawing.Size(10,10)
$DropDownLabel.size = new-object System.Drawing.Size(100,20)
$DropDownLabel.Text = "Items"
$Form.Controls.Add($DropDownLabel)
$Button = new-object System.Windows.Forms.Button
$Button.Location = new-object System.Drawing.Size(100,50)
$Button.Size = new-object System.Drawing.Size(100,20)
$Button.Text = "OK"
$Button.Add_Click({Return-DropDown})
$form.Controls.Add($Button)
我想拥有它，所以如果我输入名字为奔，姓作为Don，并使用下拉功能并选择@ gmail.com。它会返回这些值。当我试图合并这两个代码时，它将所有值更改为：
System.Windows.Forms, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089 System.Drawing, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d5 0a3a System.Windows.Forms, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089.System.Drawing, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d5 0a3a System.Windows.Forms, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089.System.Drawing, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d5 0a3a0
任何人都知道如何使此下拉正确？
欢迎回来泰勒。所以，下拉框中的返回值应该是'@ gmail.com'，没有其他的东西？ – Matt
嘿马特！很高兴再次见到你。应该有3个值。 $ return [0]应该是第一个名字。 $ return [1]应该是最后一个名字。我试图让第三个值成为3个下拉选项之一（@ gmail.com，@ yahoo.com，@ msn.com）。但是，当我们输入下拉框的代码时，它将返回上面列出的值。 –
对于初学者，您需要在下拉代码中再次使用'[void]'来启动'[System.Reflection.Assembly]''。除非这是一个复制粘贴错误 – Matt