给定的2x3阵列,我要计算在axis=0
的平均水平,但只考虑那些值大于0条件与平均numpy的
所以给出的阵列
[ [1,0],
[0,0],
[1,0] ]
我想要的输出要
# 1, 0, 1 filtered for > 0 gives 1, 1, average = (1+1)/2 = 1
# 0, 0, 0 filtered for > 0 gives 0, 0, 0, average = 0
[1 0]
我当前的代码是
import numpy as np
frame = np.array([ [1,0],
[0,0],
[1,0] ])
weights=np.array(frame)>0
print("weights:")
print(weights)
print("average without weights:")
print((np.average(frame, axis=0)))
print("average with weights:")
print((np.average(frame, axis=0, weights=weights)))
这给了我
weights:
[[ True False]
[False False]
[ True False]]
average without weights:
[ 0.66666667 0. ]
average with weights:
Traceback (most recent call last):
File "C:\Users\myuser\project\test.py", line 123, in <module>
print((np.average(frame, axis=0, weights=weights)))
File "C:\Users\myuser\Miniconda3\envs\myenv\lib\site-packages\numpy\lib\function_base.py", line 1140, in average
"Weights sum to zero, can't be normalized")
ZeroDivisionError: Weights sum to zero, can't be normalized
我不明白这个错误。我在做什么错了,我怎么能得到沿axis=0
沿大于零的所有值的平均值?谢谢!
'0,0,0过滤为> 0产生0,0,0' ......不,它不需要。你能否更准确地描述你如何处理没有找到积极因素的情况?结果应该总是0吗?结果应该是所有元素的平均值吗?是否应该计算一些其他的价值? – user2357112
加权平均值计算为平均数和权重的乘积之和除以权重之和。由于第二列的权重加起来为0(所有三个都是“假”),所以这种划分是不可能的。 – DyZ
和对发布的解决方案的反馈? – Divakar