在Java中解析以下格式的xml文件

Question

我有以下格式的xml文件，作为服务响应获取。它不是传统的xml格式，其中值包含在各自的标记中。这只是一个示例，而实际文件将包含数百个元素。我如何得到我所需要的节点（可以说“TDE-2”）以最有效的方式，把它的值在地图像{map(TenderID, TDE-2), map(ContactID, null)}

<xml version="1.0" encoding="UTF-8"?> 
<report> 
<report_header> 
<c1>TenderID</c1> 
<c2>ContactID</c2> 
<c3>Address</c3> 
<c4>Description</c4> 
<c5>Date</c5> 
</report_header> 
<report_row> 
<c1>TDE-1</c1> 
<c2></c2> 
<c3></c3> 
<c4>Tender 1</c4> 
<c5>09/30/2016</c5> 
</report_row> 
<report_row> 
<c1>TDE-2</c1> 
<c2></c2> 
<c3></c3> 
<c4>Tender 2</c4> 
<c5>10/02/2016</c5> 
</report_row> 
</report> 

Answer 1

JAXB允许你deserialise XML转换成Java对象。如果创建Java POJO以匹配XML文档模型，则可以使用JAXB对POJO中的XML进行解组。

例如：

的POJO：

Report.java：

import java.util.List; 

import javax.xml.bind.annotation.XmlElement; 
import javax.xml.bind.annotation.XmlRootElement; 

@XmlRootElement 
public class Report { 

    private List<ReportRow> reportRows; 

    public List<ReportRow> getReportRows() { 
     return reportRows; 
    } 

    @XmlElement(name = "report_row") 
    public void setReportRows(List<ReportRow> reportRows) { 
     this.reportRows = reportRows; 
    } 
} 

ReportRow.java

import javax.xml.bind.annotation.XmlElement; 

public class ReportRow { 

private String c1; 
private String c2; 
private String c3; 
private String c4; 

public String getC1() { 
    return c1; 
} 

@XmlElement 
public void setC1(String c1) { 
    this.c1 = c1; 
} 

public String getC2() { 
    return c2; 
} 

@XmlElement 
public void setC2(String c2) { 
    this.c2 = c2; 
} 

public String getC3() { 
    return c3; 
} 

@XmlElement 
public void setC3(String c3) { 
    this.c3 = c3; 
} 

public String getC4() { 
    return c4; 
} 

@XmlElement 
public void setC4(String c4) { 
    this.c4 = c4; 
} 

}

代码来读取你的XML，并将其绑定到Java对象：

import java.io.File; 

import javax.xml.bind.JAXBContext; 
import javax.xml.bind.JAXBException; 
import javax.xml.bind.Unmarshaller; 

import org.junit.Test; 

public class JaxbTest { 

    @Test 
    public void testFoo() throws JAXBException { 

     File xmlFile = new File("src/test/resources/reports.xml"); 
     JAXBContext context = JAXBContext.newInstance(Report.class, ReportRow.class); 
     Unmarshaller jaxbUnmarshaller = context.createUnmarshaller(); 
     Report report = (Report) jaxbUnmarshaller.unmarshal(xmlFile); 
     ReportRow reportYouWant = report.getReportRows().stream().filter(reportRow -> reportRow.getC1().equals("TDE-1")) 
       .findFirst().get(); 

    } 
} 

您还需要以下依赖关系添加到您的构建脚本：

compile group: 'javax.xml', name: 'jaxb-impl', version: '2.1' 
compile group: 'javax.xml', name: 'jaxb-api', version: '2.1'