如何动态加载一个Django类

从数据库我有一个文本，它必须动态加载我的意见的类。如何动态加载一个Django类

，因为我有此刻的例子是：

-projectname 
    -appname 
     -views.py 
     -templates 
      -appname 
       -index.html

在views.py

class SelectCampaign(View): 

    def get(self, request, *args, **kwargs): 

     campaign = Campaign.objects.values('campaign_name').filter(user=request.user)[0] 

     #this is where I need you to automatically load with varying campaign 
     generic_class = MyClassCampaignName1() 
     #example: generic_class = class called MyClassCampaignName1 

     return generic_class.render_index(request) 

class MyClassCampaignName1(): 

    def render_index(self, request, *args, **kwargs): 
     return render(request, 'appname/index.html', {}, context_instance=RequestContext(request))

，带来了数据库动态加载类具有相同名称的名称

来源

2015-09-04 Andres Charry Álvarez

我不认为这是Django的具体。如果不是，请查看https://stackoverflow.com/questions/1176136/convert-string-to-python-class-object – Santiago

以下是从字符串名称中获取对象的几种方法。我最喜欢getattr。

# outside.py 
class OuterDummy(): 
    def __init__(self): 
     print 'This is outer Dummy!' 

# main.py 
class InnerDummy(): 
    def __init__(self): 
     print 'This is inner Dummy!' 

if __name__ == "__main__": 
    # Method 1) Use the globals object 
    class_1 = globals().get('InnerDummy') 
    instance_1 = class_1() 
    # stdout: This is inner Dummy! 

    # Method 2) Use getattr 
    import outside 
    class_2 = getattr(outside, 'OuterDummy') 
    instance_2 = class_2() 
    # stdout: This is outer Dummy!

python main.py

来源

2015-09-05 16:11:37 pztrick

如何动态加载一个Django类

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