如果语句错误：ValueError异常：无效的字面INT（）基数为10：“”和乱序INT（）的

Question

我的代码如下：

allnums = [] 
odds = [] 
evens = [] 

number = 0 

while True: 
    number = input("Enter a number or type 'done':") 

    if number.lower() == 'done': 
     print("=============================") 
     print("Your even numbers are", str(evens)) 
     print("Your odds numbers are", str(odds)) 
     print("=============================") 
     print("Your smallest number is '"+str(allnums[0])+"'") 
     break 
    if int(number) % 2 == 0: 
     evens.append(number) 
     evens.sort() 
     allnums.append(number) 
     allnums.sort()  
    if int(number) % 2 != 0: 
     odds.append(number) 
     odds.sort() 
     allnums.append(number) 
     allnums.sort() 
    else: 
     print("Invalid input") 

我试图创建一个程序，读取数字列表并确定最低值，同时还提供偶数和奇数的列表。我遇到两个问题与我的代码，其中最小的数字是不是经常正确，例如：

Enter a number or type 'done':33 
Enter a number or type 'done':4 
Invalid input 
Enter a number or type 'done':6 
Invalid input 
Enter a number or type 'done':4 
Invalid input 
Enter a number or type 'done':6 
Invalid input 
Enter a number or type 'done':7 
Enter a number or type 'done':44 
Invalid input 
Enter a number or type 'done':88 
Invalid input 
Enter a number or type 'done':done 
============================= 
Your even numbers are ['4', '4', '44', '6', '6', '88'] 
Your odds numbers are ['33', '7'] 
============================= 
Your smallest number is '33' 

我也得到了以下错误，当我使用只是一个空格（”“）作为一个答案，这我想编写一个Print（“无效输入”）响应的东西，是不是数字或完成，但结果总是在：

Traceback (most recent call last): 
    File "XXXX", line 17, in <module> 
    if int(number) % 2 == 0: 
ValueError: invalid literal for int() with base 10: ' ' 

我知道这大多与事件的顺序做，但什么我错过了吗？

Answer 1

allnums = [] 
odds = [] 
evens = [] 

number = 0 

while True: 
    try: 
     number = input("Enter a number or type 'done':") 

     if number.lower() == 'done': 
      print("=============================") 
      print("Your even numbers are", str(sorted(evens))) 
      print("Your odds numbers are", str(sorted(odds))) 
      print("=============================") 
      print("Your smallest number is '"+str(sorted(allnums)[0])+"'") 
      break 
     elif int(number) % 2 == 0: 
      evens.append(number) 
      #evens.sort() 
      allnums.append(number) 
      #allnums.sort()  
     elif int(number) % 2 != 0: 
      odds.append(number) 
      #odds.sort() 
      allnums.append(number) 
      #allnums.sort() 
     pass 

    except: 
     print("Invalid input") 
    pass 

你确定，这是我的输出

deathnote@deathnote:~/Desktop/d$ python3 code.py 
Enter a number or type 'done':12 
Enter a number or type 'done': 
Invalid input 
Enter a number or type 'done': 
Invalid input 
Enter a number or type 'done':qwe 
Invalid input 
Enter a number or type 'done': 
Invalid input 
Enter a number or type 'done':wqew 
Invalid input 
Enter a number or type 'done':done 
============================= 
Your even numbers are ['12'] 
Your odds numbers are [] 
============================= 
Your smallest number is '12' 

Answer 2

错误消息很明显：number包含一个空格，无法将其解析为整数。如果你想标记这样的输入无效，你必须在之前测试试图将其转换为整数（或捕获这样做的错误）。

Answer 3

你有两个问题：

1. 需要检查的空间你想从它那里得到一些之前。

2. 然后要附加数字输入作为串到你的列表中，这将错误的排序结果结束，因为这将排序string而不是number。

---

allnums = [] 
odds = [] 
evens = [] 

number = 0 

    if number.lower() == 'done': 
    evens.sort() 
    odds.sort() 
    allnums.sort() 
    print("=============================") 
    print("Your even numbers are", str(evens)) 
    print("Your odds numbers are", str(odds)) 
    print("=============================") 
    print("Your smallest number is '"+str(allnums[0])+"'") 
    break 

if number.isspace(): 
    print("Invalid input") 
else: 
    number = int(number) 
    if int(number) % 2 == 0: 
     evens.append(number) 
     allnums.append(number) 
    elif int(number) % 2 != 0: 
     odds.append(number) 
     allnums.append(number) 

Answer 4

allnums = [] 
odds = [] 
evens = [] 

number = 0 

while True: 
    number = input("Enter a number or type 'done':") 

    if number.lower() == 'done': 
     print("=============================") 
     print("Your even numbers are", str(evens)) 
     print("Your odds numbers are", str(odds)) 
     print("=============================") 
     print("Your smallest number is '" + sorted(allnums)[0] + "'") 
     break 
    if not number.isnumeric(): 
     print("Invalid input") 
     continue 
    if int(number) % 2 == 0: 
     evens.append(number) 
     evens.sort() 
     allnums.append(number) 
     allnums.sort() 
    if int(number) % 2 != 0: 
     odds.append(number) 
     odds.sort() 
     allnums.append(number) 
     allnums.sort()