2014-08-28 99 views
1

这里我需要一种方法来找出两个日期之间的星期几。如果我提供'2014-08-28'和'2014-08-30'两个日期,则应返回['Friday','Saturday']如何获得javascript中两个不同日期之间的星期几

var d = new Date(); 
var weekday = new Array(7); 
weekday[0]= "Sunday"; 
weekday[1] = "Monday"; 
weekday[2] = "Tuesday"; 
weekday[3] = "Wednesday"; 
weekday[4] = "Thursday"; 
weekday[5] = "Friday"; 
weekday[6] = "Saturday"; 

var n = weekday[d.getDay()]; 

如何使用.getDay()

+1

如果您提供2013-08-28和2014-08-30,那么如何?它应该返回一个包含367项的数组吗? – 2014-08-28 13:50:02

+0

但在** 8月28日至30日之间只有一天**。 ;-)您似乎已经知道如何将* date.getDay *转换为日期名称,因此只需逐步增加早期日期并获取每日的名称,直至到达最后日期。 – RobG 2014-08-28 13:52:34

+0

@PabloMatíasGomez-我在评论OP,因此没有@ ...。 – RobG 2014-08-28 13:55:12

回答

0

那么你需要编写一些函数,最重要的是,使用Date.parse将日期转换为ms并在日期之间进行数学运算。解决方案如下。查看jsFiddle获取工作代码。 demo

var days = 3; 
var msPerDay = 1000*60*60*24; 


var nextDay = function (day , dayAfter) { 
    return Date.parse(day) + (msPerDay*dayAfter); 
} 

var daysBetween = function (from, to) { 
    return ((Date.parse(to) - Date.parse(from))/msPerDay) - 1 ; 
} 


var d1 = new Date(); 
var d2 = new Date(nextDay(d1, days)); 

var weekday = new Array(7); 
weekday[0]= "Sunday"; 
weekday[1] = "Monday"; 
weekday[2] = "Tuesday"; 
weekday[3] = "Wednesday"; 
weekday[4] = "Thursday"; 
weekday[5] = "Friday"; 
weekday[6] = "Saturday"; 


var getInbetweenWeekdays = function() { 
    var weekDays = []; 
    for (var i = 0 ; i < daysBetween(d1, d2); i++) { 
     weekDays.push(weekday[new Date(nextDay(d1, i + 1)).getDay()]); 
    } 

    return weekDays; 
} 



alert(getInbetweenWeekdays()); 

细说这一点,添加适当的getter和setter方法你会没事的,但你的漂移。

+0

哇。这是我的预期。非常感谢.. – user2587222 2014-08-28 16:28:25

+0

一般而言,您将认识到一种功能性方法。 Javascript真的很擅长它。 – 2014-08-28 16:30:54

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