Java/clojure：多字符分隔符，并保留分隔符

Question

我正在处理clojure中的一个项目，它可以与任何java类互操作，所以我的问题的答案可以是java或clojure。

基本上我需要能够将一个字符串拆分为基于给定分隔符（这将超过一个字符），但同时保留分隔符。

例如：

splitting "test:test:test" on ":" => [ "test" ":" "test" ":" "test" ] 
splitting "::test::test::" on "::" => [ "::" "test" "::" "test" "::" ] 

我一直在使用Clojure的clojure.string/split来使用的厕所，但它实际上并没有返回的分隔符。第二个最接近的是使用StringTokenizer，它返回分隔符但不接受多字符分隔符。

有谁知道任何解决方案，然后只是把字符串分解成一个字符序列并运行一个奇怪的减少它？

Answer 1

下面是建立一个正则表达式前后分隔符后，以配合间隙的版本，而不是分隔字符串本身（假设没有正则表达式的特殊字符在d）：

=> (defn split-with-delim [s d] 
    (clojure.string/split s (re-pattern (str "(?=" d ")|(?<=" d ")")))) 
#'user/split-with-delim 
=> (split-with-delim "test:test:test" ":") 
["test" ":" "test" ":" "test"] 
=> (split-with-delim "::test::test::" "::") 
["" "::" "test" "::" "test" "::"] 

Answer 2

(defn split-it [s d] 
    (interpose d (str/split s (re-pattern d)))) 

(split-it "test:test:test" ":") 
=> ("test" ":" "test" ":" "test") 

(split-it "::test::test::" "::") 
=> ("" "::" "test" "::" "test")