我试图用arrayAdapter创建一个4列列表视图,并在populateList手动添加值()将数据从字符串数组列表视图
private void populateList()
{
list = new ArrayList<HashMap<String,String>>();
HashMap<String,String> temp1 = new HashMap<String,String>();
temp1.put(FIRST_COLUMN,"Diaries");
temp1.put(SECOND_COLUMN, "Products");
temp1.put(THIRD_COLUMN, "Rs. 400");
temp1.put(FOURTH_COLUMN, "ggg Unit");
list.add(temp1);
HashMap<String,String> temp2 = new HashMap<String,String>();
temp2.put(FIRST_COLUMN,"Note Books");
temp2.put(SECOND_COLUMN, "Products");
temp2.put(THIRD_COLUMN, "Rs. 600");
temp2.put(FOURTH_COLUMN, "hhh Unit");
list.add(temp2);
}
我的问题是我要动态地添加列表项从二维数组 怎么可能?项目数与字符串数组的大小相同? ie;的
HashMap<String,String> temp1 = new HashMap<String,String>();
temp1.put(FIRST_COLUMN,"Diaries");
temp1.put(SECOND_COLUMN, "Products");
temp1.put(THIRD_COLUMN, "Rs. 400");
temp1.put(FOURTH_COLUMN, "ggg Unit");
insted的我想显示
temp1.put(FIRST_COLUMN,"myArry[i][j]");
temp1.put(SECOND_COLUMN, "myArry[i][j]");
temp1.put(THIRD_COLUMN, "myArry[i][j]");
temp1.put(FOURTH_COLUMN, "myArry[i][j]");
在for循环 也是我doubut是如何创建的HashMap动态
HI,RJ thanx为您的答复,我确切的问题是我有一个2D字符串数组,我想从字符串数组中添加这些项目listview .. – 2013-02-21 11:13:29
我认为你在动态创建'HashMap'时有问题吗?我的文章将解决这个问题,你可以使用'List'来填充你的'ListView'。 – SudoRahul 2013-02-21 11:14:46
如果这是我的字符串数组,String [] [] mDialogStrings = new String [10] [10] = {{“a”,“b”,“c”},{“d”,“e” f“},{”g“,”h“,”i“}}如何将这些项目添加到列表视图 – 2013-02-21 11:18:43