preg_replace函数删除不需要的链接

Question

我试图删除这样的事情：

<a href="http://women.domain.com">women.domain.com</a> 

我认为这应该是：

$this->tresc[$i][description]=preg_replace("/\<a(.*)href=(\"|')http:\/\/women\.domain\.com.*(\"|')(.*)\/\>/i", "",$this->tresc[$i][description]); 

，但它不工作。

因为我用这个图片，它的工作完美：

$this->tresc[$i][description]=preg_replace("/\<img(.*)src=(\"|')http:\/\/women\.domain\.com.*(\"|')(.*)\/\>/i", "",$this->tresc[$i][description]); 

Answer 1

$this->tresc[$i][description]=preg_replace("/<a href=\"(.*)\">/i", "",$this->tresc[$i][description]); 
$this->tresc[$i][description]=preg_replace("/<\/a\>/i", "",$this->tresc[$i][description]); 

Answer 2

$this->tresc[$i][description]=preg_replace("/\<a .*\>.*\<\/a\>/i", "", $this->tresc[$i][description]); 

Answer 3

$pattern = '(\<a href=["|\']+[http(s)?:\/\/]+([a-z0-9\-]+[.]){1,}+[a-z]{2,4}+[\/]+(.*)+["|\']\>+(.*)+\</a\>)'; 
$string = "click <a href='http://subdomain.sitename.tld/somedir'>here</a>"; 

var_dump(preg_replace($pattern, "", $string)); // prints "string 'click ' (length=6)"