2014-12-03 86 views
0

交易全部, 我有以下问题:我想用php函数连接到ms sqlserver2008。 在过去,它可以正常使用mssql_connect。 因为我已经更新到PHP 5.3我有一个数组的问题:PHP 5.3和sqlsrv_connect

语法:

$serverName = "sql server"; //serverName\instanceName, portNumber (default is 1433) 
$connectionInfo = array("db", "user", "pw"); 
$conn = sqlsrv_connect($serverName, $connectionInfo); 

if($conn) { 
echo "Connection established.<br />"; 
}else{ 
echo "Connection could not be established.<br />"; 
die(print_r(sqlsrv_errors(), true)); 
} 
exit; 

当我将显示页面,我得到这个数组错误:

Connection could not be established. 
Array ([0] => Array ([0] => IMSSP [SQLSTATE] => IMSSP [1] => -8 [code] => -8 [2] => An 
invalid connection option key type was received. Option key types must be strings. 
[message] => An invalid connection option key type was received. Option key types must be strings.)) 

也许有人有一个主意 ?对此,我将非常感谢

回答

0

检查MANUAL。该connectionInfo应该是一个键/值对数组:

$connectionInfo = array("Database"=>"dbName", "UID"=>"userName", "PWD"=>"password"); 
0

我认为这是数组定义,试试这个:

$connectionInfo = array("Database"=>"db", "UID"=>"user", "PWD"=>"pw");