我希望能够通过点击标题来排序表。我在网上找到了一些关于如何做到这一点的例子,但是当我尝试关注它们时,我得到了错误。任何帮助将不胜感激。这里是我用来从MySQL创建表的PHP代码。按标题排序表
<?php
session_start();
$Town = $_POST['Town'];
$Range = $_POST['Range'];
$Section = $_POST['Section'];
$con = mysql_connect('server, 'database', 'password');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ncwrpc", $con);
$sql = "SELECT * FROM `index8` WHERE `MAPID` = $Town$Range$Section LIMIT 0, 500 ";
$result = mysql_query($sql);
echo "<table border='2' cellpadding='5' cellspacing='2' bordercolor='#000000' bgcolor='#B8B8B8' >
<tr>
<h2>TOWN: $Town N - RANGE: $Range E - SECTION: $Section</h2>
<th bgcolor=\"#669999\">MAP</th>
<th bgcolor=\"#669999\">DESC. 1</th>
<th bgcolor=\"#669999\">DESC. 2</th>
<th bgcolor=\"#669999\">REMARKS</th>
<th bgcolor=\"#669999\">SURVEYOR</th>
<th bgcolor=\"#669999\">CLIENT</th>
<th bgcolor=\"#669999\">YEAR</th>
</tr>";
$color = "0";
while($row = mysql_fetch_array($result))
{
if($color == "0"){
echo "<tr>";
echo "<td bgcolor=\"#FFFFFF\"><a href=\"".$row['LINK']."\" target=\"_blank\">".$row['MAP1']."</a></td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Desc1'] . "</td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Desc2'] . "</td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Remarks'] . "</td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Surveyor'] . "</td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Client'] . "</td>";
echo "<td bgcolor=\"#FFFFFF\">" . $row['Y'] . "</td>";
echo "</tr>";
$color = "1";
}else{
echo "<tr>";
echo "<td bgcolor=\"#FFF380\"><a href=\"".$row['LINK']."\" target=\"_blank\">".$row['MAP1']."</a></td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Desc1'] . "</td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Desc2'] . "</td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Remarks'] . "</td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Surveyor'] . "</td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Client'] . "</td>";
echo "<td bgcolor=\"#FFF380\">" . $row['Y'] . "</td>";
echo "</tr>";
$color = "0";
}
}
?>
当你写“我有错误“,你应该说他们在哪里以及哪些错误。不要说“第5行”,因为我们不知道哪一行是行号。 5. – Voitcus 2013-03-24 13:52:31
这里缺少一个撇号'$ con = mysql_connect('server,'database','password');' – Voitcus 2013-03-24 13:53:25
上面没有任何错误可以正常工作。只是想添加排序。是的,上面提到的mysql _connect存在错误,我只是从这篇文章中删除了服务器名称等。我将按照下面的建议查看jquery。 – user2204589 2013-03-24 17:21:49