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我正在通过读取对象列表中的一些数据,将其转换为嵌套字典并序列化结果来创建JSON文件。所需的JSON格式如下:在将列表转换为字典时获取重复的JSON项目
{
"Employee1": {
"YYY": {
"StartRange": 11,
"EndRange": 22
}
},
"Employee2": {
"XXX": {
"StartRange": 24,
"EndRange": 56
}
}
}
但我得到这个JSON输出,而不是:
{
"Employee1": {
"YYY": {
"StartRange": 11,
"EndRange": 22
},
"XXX": {
"StartRange": 11,
"EndRange": 22
}
},
"Employee2": {
"YYY": {
"StartRange": 24,
"EndRange": 56
},
"XXX": {
"StartRange": 24,
"EndRange": 56
}
}
}
这里是我使用的代码:
public class LabelData
{
public int StartRange { get; set; }
public int EndRange { get; set; }
}
public class ConfigInfo
{
public string ParentGroup;
public string Label;
public int ID;
public int StartRange;
public int EndRange;
}
public Dictionary<string, Dictionary<string, LabelData>> GetData(List<ConfigInfo> configList)
{
var labelData = new Dictionary<string, Dictionary<string, LabelData>>();
foreach (var listItem in configList)
{
labelData[listItem.ParentGroup] = configList.Distinct().ToDictionary(x => x.Label.ToString(), row => new LabelData()
{
StartRange = Convert.ToInt32(listItem.StartRange.ToString()),
EndRange = Convert.ToInt32(listItem.EndRange.ToString())
});
}
return labelData;
}
protected void createFile()
{
List<ConfigInfo> configInfoList = new List<ConfigInfo>();
ConfigInfo configInfo = new ConfigInfo();
configInfo.ParentGroup = "Employee1";
configInfo.StartRange = 11;
configInfo.EndRange = 22;
configInfo.Label = "YYY";
configInfoList.Add(configInfo);
configInfo = new ConfigInfo();
configInfo.ParentGroup = "Employee2";
configInfo.StartRange = 24;
configInfo.EndRange = 56;
configInfo.Label = "XXX";
configInfoList.Add(configInfo);
if (!File.Exists(fileName))
{
FileStream fs = new FileStream(fileName, FileMode.Create, FileAccess.Write);
StreamWriter sw = new StreamWriter(fs);
JsonTextWriter writer = new JsonTextWriter(sw);
Dictionary<string, Dictionary<string, LabelData>> data = GetData(configInfoList);
string json = JsonConvert.SerializeObject(data,Formatting.Indented);
sw.Write(json);
sw.Close();
}
}
我觉得问题可能与两个类中都有StartRange和EndRange有关,但我不知道如何解决它。我究竟做错了什么?
我不明白你的要求。在最终期望的输出中,您希望Employee1的Label,StartRange和EndRange显示在Employee2下,并且您希望Employee2的Label,StartRange和EndRange显示在Employee1下面?如果列表中有三名员工而不是2名,会发生什么情况?如果只有1个呢? –
如果有一个雇员的输出将是 – Vinoth
如果有一个雇员的输出将是{ “Employee1”:{ “YYY”:{ “StartRange”:11, “EndRange”:22 } } }如果有三个员工输出将是{ “Employee1”:{ “YYY”:{ “StartRange”:11, “EndRange”:22 } }, “和Employee2”:{ “ YYY“:{ ”StartRange“:24, ”EndRange“:56 } }, “Employee3”: “AAA”:{ “StartRange”:56, “EndRange”:99 } } – Vinoth