我在复杂的应用程序中遇到了同样的问题。 Spring之间进来说,'blahblah'类型不是Serializable
,并确定它是正确的,下面是编译器生成代码的反汇编代码,并确保它不是Serializable。也许这也是你的问题,而解决办法就是你自己提到的,因为List实际上是一个Serializable类型。
的代码生成yield return new KeyValuePair<??? ???>(???,???);
[CompilerGenerated, DebuggerDisplay(@"\{ x = {x}, y = {y} }", Type="<Anonymous Type>")]
internal sealed class <>f__AnonymousType0<<x>j__TPar, <y>j__TPar>
{
// Fields
[DebuggerBrowsable(DebuggerBrowsableState.Never)]
private readonly <x>j__TPar <x>i__Field;
[DebuggerBrowsable(DebuggerBrowsableState.Never)]
private readonly <y>j__TPar <y>i__Field;
// Methods
[DebuggerHidden]
public <>f__AnonymousType0(<x>j__TPar x, <y>j__TPar y)
{
this.<x>i__Field = x;
this.<y>i__Field = y;
}
[DebuggerHidden]
public override bool Equals(object value)
{
var type = value as <>f__AnonymousType0<<x>j__TPar, <y>j__TPar>;
return (((type != null) && EqualityComparer<<x>j__TPar>.Default.Equals(this.<x>i__Field, type.<x>i__Field)) && EqualityComparer<<y>j__TPar>.Default.Equals(this.<y>i__Field, type.<y>i__Field));
}
[DebuggerHidden]
public override int GetHashCode()
{
int num = -576933007;
num = (-1521134295 * num) + EqualityComparer<<x>j__TPar>.Default.GetHashCode(this.<x>i__Field);
return ((-1521134295 * num) + EqualityComparer<<y>j__TPar>.Default.GetHashCode(this.<y>i__Field));
}
[DebuggerHidden]
public override string ToString()
{
StringBuilder builder = new StringBuilder();
builder.Append("{ x = ");
builder.Append(this.<x>i__Field);
builder.Append(", y = ");
builder.Append(this.<y>i__Field);
builder.Append(" }");
return builder.ToString();
}
// Properties
public <x>j__TPar x
{
get
{
return this.<x>i__Field;
}
}
public <y>j__TPar y
{
get
{
return this.<y>i__Field;
}
}
}
也许`[SecurityCritical]`试图告诉你不要使用`var`并且是更多类型特定的? – BeemerGuy 2010-11-25 14:24:03