用的EditText的Android SETERROR内部PopupWindow

02-16 13:06:21.702: W/dalvikvm(5138): threadid=1: thread exiting with uncaught exception (group=0x4001d560) 
02-16 13:06:21.713: E/AndroidRuntime(5138): FATAL EXCEPTION: main 
02-16 13:06:21.713: E/AndroidRuntime(5138): android.view.WindowManager$BadTokenException: Unable to add window -- token [email protected] is not valid; is your activity running? 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.view.ViewRoot.setView(ViewRoot.java:533) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at  android.view.WindowManagerImpl.addView(WindowManagerImpl.java:200) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:114) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.view.Window$LocalWindowManager.addView(Window.java:424) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.widget.PopupWindow.invokePopup(PopupWindow.java:907) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.widget.PopupWindow.showAsDropDown(PopupWindow.java:819) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.widget.TextView.showError(TextView.java:3438) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.widget.TextView.setError(TextView.java:3409) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.widget.TextView.setError(TextView.java:3373) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at com.example.zoopiekuj.MenuActions$5.onClick(MenuActions.java:185) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.view.View.performClick(View.java:2538) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.view.View$PerformClick.run(View.java:9152) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.os.Handler.handleCallback(Handler.java:587) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.os.Handler.dispatchMessage(Handler.java:92) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.os.Looper.loop(Looper.java:130) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at android.app.ActivityThread.main(ActivityThread.java:3687) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at java.lang.reflect.Method.invokeNative(Native Method) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at java.lang.reflect.Method.invoke(Method.java:507) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:867) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:625) 
02-16 13:06:21.713: E/AndroidRuntime(5138):  at dalvik.system.NativeStart.main(Native Method)

所以我有输入的EditText内部PopupWindow和IM试图通过使用一些检查并用SETERROR方法SETING错误后验证此字段。以及即时获得以上错误：/任何想法有什么不对？用的EditText的Android SETERROR内部PopupWindow

 final float scale = context.getResources().getDisplayMetrics().density; 
    int popupWidth = (int) (300 * scale + 0.5f); 
    int popupHeight = (int) (345 * scale + 0.5f); 

    LinearLayout viewGroup = (LinearLayout) context.findViewById(R.id.popupreg); 
    LayoutInflater layoutInflater = (LayoutInflater) context 
    .getSystemService(Context.LAYOUT_INFLATER_SERVICE); 

    layout = layoutInflater.inflate(R.layout.logregpopup, viewGroup); 
     popup = new PopupWindow(context); 
     popup.setContentView(layout); 
     popup.setWidth(popupWidth); 
     popup.setHeight(popupHeight); 
     popup.setFocusable(true); 
     popup.setBackgroundDrawable(new BitmapDrawable()); 
     popup.showAtLocation(layout, Gravity.BOTTOM,0,90); 

     Button btnreg = (Button) layout.findViewById(R.id.btnregister); 
     btnreg.setOnClickListener(new OnClickListener() { 
      @Override 
      public void onClick(View arg0) { 
       progressDialog = ProgressDialog.show(context, "Ładowanie", "poczekaj proszę !"); 

       getmethod = 1; 

       int err = 0; 

       TextHelper thelper = new TextHelper(); 

       EditText login  = (EditText) layout.findViewById(R.id.reglogin); 
       EditText email  = (EditText) layout.findViewById(R.id.regemail); 
       EditText pass1  = (EditText) layout.findViewById(R.id.regpass1); 
       EditText pass2  = (EditText) layout.findViewById(R.id.regpass2); 



       String l = login.getText().toString(); 
       String e = email.getText().toString(); 
       String p1 = pass1.getText().toString(); 
       String p2 = pass2.getText().toString(); 

       if(l.equals("") || l.length() < 3){ 
        err++; 
        login.setError("Login musi mieć co najmniej 3 znaki"); 
       }

我可以从登录字段获得文本没有问题，所以它只是setError有问题。

来源

2013-02-16 Gmatkowski

您是否找到解决方案？ – 2013-07-16 08:20:29

这一行的上下文是调用活动吗？

popup = new PopupWindow（context）;

如果它是一个死/过时的活动或应用程序上下文，它将会像这样失败。

来源

2013-02-16 13:05:47 Larry

这个弹出不是一个问题（我认为），因为它工作得很好。问题是当 login.setError（“Login musimiećco najmniej 3 znaki”）;发生了。 – Gmatkowski 2013-02-16 14:15:15

接受的答案不适合我 – 2017-06-19 16:37:09

用的EditText的Android SETERROR内部PopupWindow

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