试图访问Twitter流API与C

Question

我从C libcurl get output into a string得到的代码。我修改了它，我想用它来访问Twitter流。我在代码中添加了curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json");和curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password");。但问题是，每当我执行它时，都没有输出。什么是这个问题？谢谢。

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 
#include <curl/curl.h> 

struct string { 
    char *ptr; 
    size_t len; 
}; 

void init_string(struct string *s) { 
    s->len = 0; 
    s->ptr = malloc(s->len+1); 
    if (s->ptr == NULL) { 
    fprintf(stderr, "malloc() failed\n"); 
    exit(EXIT_FAILURE); 
    } 
    s->ptr[0] = '\0'; 
} 

size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s) 
{ 
    size_t new_len = s->len + size*nmemb; 
    s->ptr = realloc(s->ptr, new_len+1); 
    if (s->ptr == NULL) { 
    fprintf(stderr, "realloc() failed\n"); 
    exit(EXIT_FAILURE); 
    } 
    memcpy(s->ptr+s->len, ptr, size*nmemb); 
    s->ptr[new_len] = '\0'; 
    s->len = new_len; 

    return size*nmemb; 
} 

int main(void) 
{ 
    CURL *curl; 
    CURLcode res; 

    curl = curl_easy_init(); 
    if(curl) { 
    struct string s; 
    init_string(&s); 

    curl_easy_setopt(curl, CURLOPT_URL, "http://stream.twitter.com/1/statuses/sample.json"); 
    curl_easy_setopt(curl, CURLOPT_USERPWD, "neilmarion:my_password"); 
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc); 
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s); 
    res = curl_easy_perform(curl); 

    printf("%s\n", s.ptr); 
    free(s.ptr); 

    /* always cleanup */ 
    curl_easy_cleanup(curl); 
    } 
    return 0; 
} 

Answer 1

最快的下一步可能是设置CURLOPT_HEADER，以在头文件输出中包含头文件。最有可能的是，我猜测它在安全方面失败了，你会在头文件中看到细节。