2014-08-31 135 views
0

根据两组闹钟,开始时间和停止时间,我的应用程序会触发一次意图两次。我现在正试图扩展这一点,以便可以在多天内指定设置的闹钟,并可以选择重复。在特定日期重复报警

我在目标设备上有GCM中接收到的8个整数值,repeat = 1,sun = 1,mon = 1等...如果选择了一天或重复,则它的值为1。

如何在特定日期重复闹钟?

我可以把收到的价值,0111110将是所有的周日,例如...然后遍历他们并创建警报的价值是1?

我不知道如何构造这个,可以有人建议?

谢谢。

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解析您的响应,然后根据结果 – 2014-08-31 11:01:59

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建立一个日常报警安排一个alarmanager,然后发射时检查当天或设置多达七个weelky警报 – pskink 2014-08-31 11:05:22

回答

0

得到它的工作,使用下面的...也许有些人会觉得这有用

   int[] daysOfWeek = new int[7]; 
      int[] daysOfWeekValue = new int[7]; 
      //parce from GCM values recieved 
        final int sunday = Integer.parseInt(sun); 
        daysOfWeek[0] = sunday; 
        final int monday = Integer.parseInt(mon); 
        daysOfWeek[1] = monday; 
        final int tuesday = Integer.parseInt(tue); 
        daysOfWeek[2] = tuesday; 
        final int wednesday = Integer.parseInt(wed); 
        daysOfWeek[3] = wednesday; 
        final int thursday = Integer.parseInt(thu); 
        daysOfWeek[4] = thursday; 
        final int friday = Integer.parseInt(fri); 
        daysOfWeek[5] = friday; 
        final int saturday = Integer.parseInt(sat); 
        daysOfWeek[6] = saturday; 
        final int repeating = Integer.parseInt(repeat); 


        daysOfWeekValue[0]=1; 
        daysOfWeekValue[1]=2; 
        daysOfWeekValue[2]=3; 
        daysOfWeekValue[3]=4; 
        daysOfWeekValue[4]=5; 
        daysOfWeekValue[5]=6; 
        daysOfWeekValue[6]=7; 

        for (int i=0; i<daysOfWeek.length; i++) 
        { 
         if(daysOfWeek[i]==1){ 
         Log.i(TAG, "Set alarm on day: " + daysOfWeekValue[i]); 

        final Calendar calNow = Calendar.getInstance(); 
        final Calendar calSet = (Calendar) calNow.clone(); 

        calSet.set(Calendar.DAY_OF_WEEK, daysOfWeekValue[i]);// 1 for      sunday, 2 for monday etc 
        calSet.set(Calendar.HOUR_OF_DAY, starthour); 
        calSet.set(Calendar.MINUTE, startmin); 
        calSet.set(Calendar.SECOND, 0); 
        calSet.set(Calendar.MILLISECOND, 0); 

        .....