的MySQL：查询比较

Question

我想获得一个记录集，我可以用一个关系表比较结果：

character_abilities 
id ability_id character_id 
1  1    43 
2  2    43 
3  5    43 
4  7    43 
5  8    43 
6  9    43 
7  1    75 
8  2    75 
9  3    75 
10 5    75 

我想获得这样的结果：

ability_id_1 character_id_1 ability_id_2 character_id_2 
1    43    1    75 
2    43    2    75 
NULL   NULL    3    75 
5    43    5    75 
7    43    NULL   NULL 
8    43    NULL   NULL 
9    43    NULL   NULL 

对于这个结果，我认为做这样的事情，但没有成功：

SELECT character_1.ability_id AS ability_id_1, character_1.character_id AS character_id_1, character_2.ability_id AS ability_id_2, character_2.character_id AS character_id_2 
FROM character_abilities AS character_1 
RIGHT JOIN character_abilities AS character_2 
ON character_2.character_id = 2 AND character_1.ability_id = character_2.ability_id 
WHERE character_1.character_id = 1 AND character_1.ability_id = character_2.ability_id 

不幸的是，这只是返回每个角色都有共同的能力。

我的问题是：
我可以编码查询来获取每个字符的道具像结果的例子吗？ 我应该为每个角色查询并合并它们吗？

Answer 1

如果我理解这个问题，听起来像是一个FULL OUTER JOIN的候选人，这是MySQL不具备的。 See this question for alternatives.