腓循环throught XML节点

Question

我对XML文件中像

<response> 
<tag1> 
    <item> 
     <id>106</id> 
     <title>DG</title> 
    </item> 
    <item> 
     <id>105</id> 
     <title>AC</title> 
    </item> 
</tag1> 
<tag2> 
    <item> 
     <id>1</id> 
     <title>DjG</title> 
    </item> 
    <item> 
     <id>15</id> 
     <title>AoC</title> 
    </item> 
</tag2> 
</response> 

我想这个代码以提取ID和标题

$dom = new DomDocument(); 
    $dom->load('xml.xml'); 
    $xpath = new DOMXPath($dom); 

    foreach($xpath->evaluate('//response/*') as $node){ 
    $params =$xpath->evaluate('//response/' .$node->nodeName . '/item/*'); 
     foreach($params as $child) { 
      echo $node->nodeName ." = " .$child->nodeName ." = " .$child->nodeValue ."\n<br>"; 
     } 
    } 

，但我得到的结果，例如

<br>tag1 = id = 106 
<br>tag1 = title = DG 
<br>tag1 = id = 105 
<br>tag1 = title = AC 
<br>tag2 = id = 1 
<br>tag2 = title = DjG 
<br>tag2 = id = 15 
<br>tag2 = title = AoC 

但我需要像这样得到

TAG1 = 106 = DG
TAG1 = 105 = AC
TAG2 = 1 = DJG
TAG2 = 15 = AoC的

Answer 1

在第二foreach ，只是目标$node->nodeName，然后在内部的foreach目标每个id一个标题。

foreach($xpath->evaluate('//response/*') as $node) { 
    $tag = $node->nodeName; 
    $params = $xpath->evaluate("//$tag/*"); 
    foreach($params as $child) { 
     $id = $xpath->evaluate('string(./id)', $child); 
     $title = $xpath->evaluate('string(./title)', $child); 
     echo $tag ." = " .$id ." = " .$title ."\n<br>"; 
    } 
} 

Sample Output

还是SimpleXML版本：

$xml = simplexml_load_file('xml.xml'); 
foreach($xml as $tag =>$node) { 
    foreach($node as $item => $child) { 
     echo $tag ." = " .$child->id ." = " .$child->title ."\n<br>"; 
    } 
} 

Sample Output

Answer 2

使用此代码：

$dom = new DomDocument(); 
$dom->load('xml.xml'); 
$xpath = new DOMXPath($dom); 
foreach($xpath->evaluate('//response/*') as $node){ 
    $params =$xpath->evaluate('//response/' .$node->nodeName . '/*'); 

    foreach($params as $child) 
    { 
     echo $node->nodeName ." = " .$child->getElementsByTagName('id')->item(0)->textContent ." = " .$child->getElementsByTagName('title')->item(0)->textContent ."\n<br>"; 
    } 
} 

Answer 3

DOMXpath的第二个参数::评估（）是上下文节点。如果你不用斜杠启动XPath表达式，它将与它相关。因此，在一个循环中，您通常希望将当前节点用作表达式的上下文。

foreach ($xpath->evaluate('/absolute-expression') as $node) { 
    var_dump(
    $xpath->evaluate('relative-expression', $node) 
); 
} 

XPath（与CSS选择器不同）可以获取沿不同轴的元素属性。你可以得到当地名（不带命名空间前缀）父节点：

local-name(parent::*)

利用这一点，你可以用一个循环遍历item元素解决问题。

实施例：

$dom = new DomDocument(); 
$dom->loadXml($xml); 
$xpath = new DOMXPath($dom); 

foreach ($xpath->evaluate('//response/*/item') as $node) { 
    echo 
    $xpath->evaluate('local-name(parent::*)', $node), ' = ', 
    $xpath->evaluate('string(id)', $node), ' = ', 
    $xpath->evaluate('string(title)', $node), "\n"; 
} 

输出：

tag1 = 106 = DG 
tag1 = 105 = AC 
tag2 = 1 = DjG 
tag2 = 15 = AoC 

只是，如果需要调用源的每个第一级节点（TAG1，TAG2）。你将需要两个循环。像输出由标签*元素节点分组的项目一样。

$dom = new DomDocument(); 
$dom->loadXml($xml); 
$xpath = new DOMXPath($dom); 

foreach ($xpath->evaluate('//response/*') as $node) { 
    echo 
    $xpath->evaluate('local-name()', $node), 
    "\n--------\n"; 
    foreach ($xpath->evaluate('item', $node) as $item) { 
    echo 
     $xpath->evaluate('string(id)', $item), ' = ', 
     $xpath->evaluate('string(title)', $item), "\n"; 
    } 
    echo "\n"; 
} 

输出：

tag1 
-------- 
106 = DG 
105 = AC 

tag2 
-------- 
1 = DjG 
15 = AoC