如何根据Python中的列对文本文件进行排序？包含以下数据

Question

我有一个文件（file.txt的）：

192.168.10.1/16, 22, 3265, tcp 
172.144.32,2/34, 22, 21, udp 
10.128.16.234/8, 0, 20, icmp 

我需要通过cloumn [0]，cloumn [1]和柱[2]

排序此

Answer 1

我的解决方案是创建这样的元组列表（一个元组每条线）：

(data_in_column_of_interest, entire_line) 

凡data_in_column_of_interest是任何数据类型，entire_line是字符串。

然后就对这个文件列表：包含文件：

def sortLinesByColumn(readable, column, columnt_type): 
    """Returns a list of strings (lines in readable file) in sorted order (based on column)""" 
    lines = [] 

    for line in readable: 
     # get the element in column based on which the lines are to be sorted 
     column_element= columnt_type(line.split(',')[column-1]) 
     lines.append((column_element, line)) 

    lines.sort() 

    return [x[1] for x in lines] 


with open('G:/Ftest/data.txt') as f: 
    # sort the lines based on column 1, and column 1 is type int 
    sorted_lines = sortLinesByColumn(f, 1, int) 

    for l in sorted_lines: 
     print(l) 

输入

1, Bob, 123 
5, Mary, 112 
0, Allen, 2421 
1, lucy, 341 

输出：一个字符串列表：

0, Allen, 2421 
1, Bob, 123 
1, lucy, 341 
5, Mary, 112