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我已经把我的代码的简化版本放在这里。我想要做的是从输入文件中读取每一行并将其存储在“fifo”类中。但是在每个商店之前,我尝试打印先前的fifo值(这是为了调试)。我所看到的是,即使在我调用fifo.add函数之前,以前的值也会被覆盖。 getline函数本身自己覆盖fifo。有人能告诉我这里发生了什么吗?将外部变量传递给一个类C++
//fifo.h
#ifndef FIFO_H_
#define FIFO_H_
class fifo {
private:
char* instr_arr;
int head;
int tail;
public:
fifo();
fifo(int,int);
void add(char*);
void print_instruction(void);
};
#endif
//fifo.cpp
#include "fifo.h"
#include <iostream>
//using namespace std;
fifo::fifo() {
head = 0;
tail = 0;
instr_arr = "NULL";
}
fifo::fifo(int h, int t) {
head = h;
tail = t;
}
void fifo::add (char *instr) {
instr_arr = instr;
}
void fifo::print_instruction (void) {
std::cout << instr_arr << std::endl;
}
//code.cpp
#include <iostream>
using namespace std;
#include <fstream>
using namespace std;
#include "fifo.h"
#define MAX_CHARS_INLINE 250
int main (int argc, char *argv[]) {
char buf[MAX_CHARS_INLINE]; //Character buffer for storing line
fifo instruction_fifo; //FIFO which stores 5 most recent instructions
const char *filename = argv[1];
ifstream fin;
fin.open(filename);
while(!fin.eof()) {
std::cout << buf << std::endl;
fin.getline(buf, MAX_CHARS_INLINE);
instruction_fifo.print_instruction(); //This instruction prints the line which was read from getline above!! Why??
instruction_fifo.add(buf);
}
return 0;
}
我建议使用'std :: string',而不是'char *'。而不是使用'while(!eof())' – chris
如果这不是一个练习,STL是你的朋友 –