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鉴于我在JavaScript变量“数据”Jquery的parseHTML没有给预期的对象
<div class="packery-item">
<img class="rsImg" src="/media/VERSIONS/images/blog/2013/04/heart-watercolor1_featured_image.jpg" alt="Article illustration"/>
</div>
<div class="packery-item">
<img class="rsImg" src="/media/VERSIONS/images/blog/2013/04/planning_featured_image.jpg" alt="Article illustration"/>
</div>
<div class="packery-item">
<img src="/media/VERSIONS/images/galleries/2013/04/fashion_slideshow.jpg" alt="" />
</div>
当我运行$(data)
返回这样的HTML字符串:
[div.packery-item, text, div.packery-item, text, div.packery-item, text, div.packery-item, text, div.packery-item, text, div.packery-item, constructor: function, init: function, selector: "", jquery: "1.8.3", size: function…]
我希望它返回只有div.packery-item的列表。我做错了什么?
似乎显示罚款:: http://jsfiddle.net/Fw7vz/ – 2013-05-02 03:17:22
你可以发布你的脚本? – 2013-05-02 03:17:47
标签之间的换行符和空格创建包含空格的文本节点。 – Barmar 2013-05-02 03:18:54