我在显示多达20个列表的搜索结果页面上有谷歌地图。这20个列表是从一个mysql查询中拉出来的,并在页面上循环。那部分工作正常。Google Maps(api v3) - 通过mysql查询结果循环到地理编码并在地图上放置多个标记
但是,谷歌地图(也为我地理编码的地址),只显示第一个列表。我不知道如何让它遍历每个列表并将它们全部放在地图上。
我敢肯定,一旦我得到它,它会很容易地遵循和理解,但我只是没有从头开始工作的印章。谷歌的开发人员文档也没有太多的帮助要么....
任何帮助非常感谢!
** * ** * ** * UPDATE质疑* ** * ** *
答案提供我不能看不到工作....问题是,在修复之前,页面显示了所有列表,但只映射了1.实现答案后,页面只显示第一个列表,并且地图完全不显示。
我做了修剪A & B版本。这基本上是在整个页面的代码全贴:
版本1:这显示在页面上的所有目录,但只映射第一上市:
<?php
mysql_select_db($database_db, $db);
$query_my_query = "SELECT * FROM biz WHERE state = 'MO' and city = 'springfield' order by name asc limit 0,5 ";
$my_query = mysql_query($query_my_query, $db) or die(mysql_error());
$row_my_query = mysql_fetch_assoc($my_query);
$totalRows_my_query = mysql_num_rows($my_query);
$address = $row_my_query['address'];
$city = $row_my_query['city'];
$state = $row_my_query['state'];
?>
<script type="text/javascript" src="//maps.googleapis.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var geocoder;
var map;
function initialize() {
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(34.052234,-118.243685);
var address = '<?php echo $address.', '.$city.', '.$state; ?>';
var myOptions = {
zoom: 14,
center: latlng,
mapTypeId: google.maps.MapTypeId.ROADMAP
}
map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);
geocoder.geocode({ 'address': address}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
map.setCenter(results[0].geometry.location);
var marker = new google.maps.Marker({
map: map,
position: results[0].geometry.location
});
} else {
alert("Geocode was not successful for the following reason: " + status);
}
});
}
</script>
<head>
<title>TEST</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" >
</head>
<body onload="initialize()">
<div>
<?php do { // horizontal looper?>
<?php echo $row_my_query['name'].' '.$row_my_query['address'].' '.$row_my_query['city'].', '.$row_my_query['state']; ?>
<?php echo substr($row_my_query['zip'],0,5); ?><br>
<?php $row_my_query = mysql_fetch_assoc($my_query);
} while ($row_my_query); //end horizontal looper ?>
</div>
<div id="map_canvas" style="width: 300px; height: 300px;"></div>
</body>
</html>
这里是V2:这只结束了显示1页在页面上显示,并且地图根本不起作用:
<?php
mysql_select_db($database_db, $db);
$query_my_query = "SELECT * FROM biz WHERE state = 'MO' and city = 'springfield' order by name asc limit 0,5 ";
$my_query = mysql_query($query_my_query, $db) or die(mysql_error());
$row_my_query = mysql_fetch_assoc($my_query);
$totalRows_my_query = mysql_num_rows($my_query);
$address = $row_my_query['address'];
$city = $row_my_query['city'];
$state = $row_my_query['state'];
?>
<script type="text/javascript" src="//maps.googleapis.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var geocoder;
var map;
function initialize() {
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(34.052234,-118.243685);
var addresses = [];
<?php while ($row = mysql_fetch_assoc($my_query)) { ?>
addresses.push(<?php echo '"' . $row['address'].', '.$row['city'].', '.$row['state'] . '"'; ?>);
<?php } ?>
var myOptions = {
zoom: 14,
center: latlng,
mapTypeId: google.maps.MapTypeId.ROADMAP
}
map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);
for(i in addresses) {
var address = addresses[i];
geocoder.geocode({ 'address': address}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
map.setCenter(results[0].geometry.location);
var marker = new google.maps.Marker({
map: map,
position: results[0].geometry.location
});
} else {
// alert("Geocode was not successful for the following reason: " + status);
}
});
}
</script>
<head>
<title>TEST</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" >
</head>
<body onload="initialize()">
<div>
<?php do { // horizontal looper?>
<?php echo $row_my_query['name'].' '.$row_my_query['address'].' '.$row_my_query['city'].', '.$row_my_query['state']; ?>
<?php echo substr($row_my_query['zip'],0,5); ?><br>
<?php $row_my_query = mysql_fetch_assoc($my_query);
} while ($row_my_query); //end horizontal looper ?>
</div>
<div id="map_canvas" style="width: 300px; height: 300px;"></div>
</body>
</html>
请帮忙!!我不能为了我的生活想出如何解决这个问题,但我知道答案肯定在我面前。
感谢一如既往....
感谢您的回复。它已经过去了,但我迫不及待地想要在早上尝试。我会让你知道它是怎么回事。 – Kevin 2012-02-06 09:31:23
我试过这个解决方案,但无法让它工作。现在,该页面只显示第一个列表,而不是显示所有列表并仅映射第一个列表,而地图完全不显示。 – Kevin 2012-02-09 07:40:00