绑对方现在我有三个下拉菜单。页面加载时仅显示第一个下拉菜单。一旦选择了该菜单中的选项,就会出现第二个菜单。我正在尝试对第二个和第三个菜单执行相同的操作,但它不起作用。下面是我的HTML和JS代码,我做错了什么?多重下拉菜单中的JavaScript
function choose() {
if (document.getElementById('filter1').value == 'genre') {
document.getElementById('items').style.display = 'block';
document.getElementById('items2').style.display = 'none';
document.getElementById('items3').style.display = 'none';
document.getElementById('items4').style.display = 'none';
} else if (document.getElementById('filter1').value == 'year') {
document.getElementById('items').style.display = 'none';
document.getElementById('items2').style.display = 'block';
document.getElementById('items3').style.display = 'none';
document.getElementById('items4').style.display = 'none';
} else if (document.getElementById('filter1').value == 'director') {
document.getElementById('items').style.display = 'none';
document.getElementById('items2').style.display = 'none';
document.getElementById('items3').style.display = 'block';
document.getElementById('items4').style.display = 'none';
} else if (document.getElementById('filter1').value == 'actor') {
document.getElementById('items').style.display = 'none';
document.getElementById('items2').style.display = 'none';
document.getElementById('items3').style.display = 'none';
document.getElementById('items4').style.display = 'block';
} else {
document.getElementById('items').style.display = 'none';
document.getElementById('items2').style.display = 'none';
document.getElementById('items3').style.display = 'none';
document.getElementById('items4').style.display = 'none';
}
}
function check() {
if (document.getElementById('items').style.display == 'block') {
document.getElementById('filter').style.display = 'block';
}
}
<div class="col-md-4">
<div class="dropdown">
<select id="filter1" name="filter1" onclick="choose()">
<option value=NULL>Filter 1</option>
<option value="genre">Genre</option>
<option value="year">Year</option>
<option value="director">Director name</option>
<option value="actor">Actor name</option>
<!-- Insert function to call server -->
</select>
</div>
</div>
<div class="col-md-4">
<div class="dropdown">
<select id="items" name="items" style="display: none">
<option value=NULL>Filter 2</option>
<option value="year">Year</option>
<option value="director">Director name</option>
<option value="actor">Actor name</option>
</select>
<select id="items2" name="items" style="display: none">
<option value=NULL>Filter 2</option>
<option value="genre">Genre</option>
<option value="director">Director name</option>
<option value="actor">Actor name</option>
</select>
<select id="items3" name="items" style="display: none">
<option value=NULL>Filter 2</option>
<option value="genre">Genre</option>
<option value="year">Year</option>
<option value="actor">Actor name</option>
</select>
<select id="items4" name="items" style="display: none">
<option value=NULL>Filter 2</option>
<option value="genre">Genre</option>
<option value="year">Year</option>
<option value="director">Director name</option>
</select>
</div>
</div>
<div class="col-md-4">
<div class="dropdown">
<select id="filter" name="filter" style="display: none">
<option value=NULL>Filter 3</option>
<option value="2">Director name</option>
<option value="3">Actor name</option>
</select>
</div>
</div>
定义“不工作”。它在哪里/具体如何失败?当你调试这个时,它会出错哪里?发生了什么,你期望发生什么? – David
没有点击事件绑定到其他3个选择。 – Shilly
另外一个建议:如果你更换IDS项目,items2,items3,items4到dropdown_genre,dropdown_year,dropdown_director和dropdown_genre,你的if/else块可以完全去除,因为的document.getElementById( '过滤器1')的'价值值'会给你显示下拉的ID,而不是单独检查每个值。 – Shilly