2011-06-28 65 views
1

我想不通,为什么我得到这个错误:的boost ::支持ASIO :: async_read绑定编译错误

/usr/local/include/boost/asio/impl/read.hpp: In member function ‘void boost::asio::detail::read_op<AsyncReadStream, boost::asio::mutable_buffers_1, CompletionCondition, ReadHandler>::operator()(const boost::system::error_code&, size_t, int) [with AsyncReadStream = boost::asio::basic_stream_socket<boost::asio::ip::tcp, boost::asio::stream_socket_service<boost::asio::ip::tcp> >, CompletionCondition = boost::asio::detail::transfer_at_least_t, ReadHandler = boost::function<void()(long unsigned int)>]’: 
/usr/local/include/boost/asio/impl/read.hpp:263: instantiated from ‘void boost::asio::async_read(AsyncReadStream&, const MutableBufferSequence&, CompletionCondition, ReadHandler) [with AsyncReadStream = boost::asio::basic_stream_socket<boost::asio::ip::tcp, boost::asio::stream_socket_service<boost::asio::ip::tcp> >, MutableBufferSequence = boost::asio::mutable_buffers_1, CompletionCondition = boost::asio::detail::transfer_at_least_t, ReadHandler = boost::function<void()(long unsigned int)>]’ 
src/communicator/protocol/Command.cc:34: instantiated from here 
/usr/local/include/boost/asio/impl/read.hpp:215: error: no match for call to ‘(boost::function<void()(long unsigned int)>) (const boost::system::error_code&, const long unsigned int&)’ 
/usr/local/include/boost/function/function_template.hpp:1007: note: candidates are: typename boost::function1<R, T1>::result_type boost::function1<R, T1>::operator()(T0) const [with R = void, T0 = long unsigned int] 
make: *** [src/communicator/protocol/Command.o] Error 1 

这里我的课: Command.hh

namespace communicator {            
    namespace protocol {             
    namespace in {              
     class Command : public boost::enable_shared_from_this<Command> { 
     public:               
     ~Command();             

     typedef boost::shared_ptr<Command>  pointer;    

     void got_newline();           

     protected:              
     Command(tcp::socket& socket, structure::Client& client) :  
      m_socket(socket), m_client(client) {}; 

     void endParsing(); 

     tcp::socket&   m_socket;        

     structure::Client&  m_client;        
     char     m_newline[2];       
     private:        

     };                
    } 
} 

Command.cc :

namespace communicator { 
    namespace protocol { 
    namespace in { 

     void Command::endParsing() { 
     boost::function<void()> cb = boost::bind(&Command::got_newline, 
              shared_from_this()); 
     boost::asio::async_read(m_socket, 
           boost::asio::buffer(m_newline, 2), 
           boost::asio::transfer_at_least(2), 
**ERROR POINTING THIS LINE**         cb); 
     } 

     void Command::got_newline() { 
     if (m_newline[0] == '\r' && m_newline[1] == '\n') { 
      std::cout << "End" << std::endl; 
      } 
     } 

    } 
    } 
} 

检查代码块上的“** Error pointing this line **”,这是它存在问题的原因......不知道为什么,一次又一次打破了我的头......

感谢您的帮助

我已删除了清楚起见,一些代码,如果你有任何问题,请不要犹豫

回答

3

您完成处理程序的签名是不正确的,考虑这个例子

#include <boost/asio.hpp> 

#include <boost/function.hpp> 
#include <boost/bind.hpp> 

void 
foo() 
{ 

} 

int 
main() 
{ 
    boost::asio::io_service io_service; 
    boost::asio::ip::tcp::socket socket(io_service); 

    char buf[2]; 

    // this compiles file 
    boost::asio::async_read(
      socket, 
      boost::asio::buffer(buf), 
      boost::asio::transfer_at_least(2), 
      boost::bind(&foo) 
      ); 

    // this does not 
    boost::function<void()> cb = boost::bind(&foo); 
    boost::asio::async_read(
      socket, 
      boost::asio::buffer(buf), 
      boost::asio::transfer_at_least(2), 
      cb 
      ); 

} 

boost::bind是足够聪明的errorbytes_transferred参数不传递给您绑定的函数指针。 Asio图书馆的作者有一个detailed blog post关于使用绑定与图书馆。这是值得的阅读。

+0

谢谢!那怎么样,对我来说看起来差不多,不是吗? – TheSquad

+0

一个+1的答案,如果我可以,我会给你第二个链接到博客帖子,谢谢,今天又学到了一些东西^^ –

1

的async_ *操作需要回调函数不同的签名:

void handler(
    const boost::system::error_code& error, // Result of operation. 
    std::size_t bytes_transferred   // Number of bytes read. 
); 

请在有一些例子如何编写和调用这个回调处理程序的文档更深入的了解。

+1

这是该类的shared_ptr:public shared_from_this <>,它在其他类上运行良好,这不是编译器所抱怨的。谢谢 – TheSquad

+0

不幸的是,我做到了,这就是为什么我不明白...我打电话给一个简单的void()函数,我的回调是一个boost :: function ...我们真的不能让它更简单: - /。 – TheSquad

+0

不,你没有,请看看[这个页面](http://www.boost.org/doc/libs/1_36_0/doc/html/boost_asio/reference/async_read/overload1.html)。有我发布的回调签名,不是void()函数,它需要两个参数! –

相关问题