我在我的网站上有一个民意调查,它显示每个答案旁边的单选按钮。当用户选择一个选项并提交时,即时通过ajax运行一个php脚本,将值或选中的单选按钮插入到表中。获取单选按钮值并通过ajax发送到php
我的Ajax正在运行,但当前每行插入一行0,所以它没有从单选按钮中获取值。任何帮助,将不胜感激。
HTML:
<form id="poll_form" method="post" accept-charset="utf-8">
<input type="radio" name="poll_option" value="1" id="poll_option" /><label for='1'> Arts</label><br />
<input type="radio" name="poll_option" value="2" id="poll_option" /><label for='2'> Film</label><br />
<input type="radio" name="poll_option" value="3" id="poll_option" /><label for='3'> Games</label><br />
<input type="radio" name="poll_option" value="4" id="poll_option" /><label for='4'> Music</label><br />
<input type="radio" name="poll_option" value="5" id="poll_option" /><label for='5'> Sports</label><br />
<input type="radio" name="poll_option" value="6" id="poll_option" /><label for='6'> Television</label><br />
<input type="submit" value="Vote →" id="submit_vote" class="poll_btn"/>
</form>
AJAX:
$("#submit_vote").click(function(e)
{
var option=$('input[type="radio"]:checked').val();
$optionID = "="+optionID;
$.ajax({
type: "POST",
url: "ajax_submit_vote.php",
data: {"optionID" : $optionID}
});
});
PHP:(缩短版)
if($_SERVER['REQUEST_METHOD'] == "POST"){
//Get value from posted form
$option = $_POST['poll_option'];
//Insert into db
$insert_vote = "INSERT into poll (userip,categoryid) VALUES ('$ip','$option')";
提前感谢!
'数据:{ “optionID”:$ optionID}'应该是'数据:{optionID:$ optionID}' – tiagojpdias 2013-04-04 14:47:00
您是否获得在选项变量的正确值开始用?如果不尝试 '$('input [type =“radio”] ['name = poll_option']:checked')。val();' 注意在类型之后添加了['name-poll_option'] =“无线电” – Keeleon 2013-04-04 14:48:37