这是什么错误使触发器？

Question

我做了一个触发这样的：

create trigger mytrigger 
before 
insert on 
person4 
for each row 
begin 
if new.salary < 5000 then 
    set new.salary = 6000; 
end if; 
end; 

这里的工资表person4的属性，我正在为这个触发。但是，它显示错误：#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 8

为什么会出现这种情况？语法是完全正确的。那为什么会发生？

Answer 1

触发器看起来不错，唯一缺少的是分隔符。

我刚刚创建与样品表TRIGER这里是

delimiter // 
create trigger mytrigger before insert on person4 
for each row 
begin 
if new.salary < 5000 then 
    set new.salary = 6000; 
end if; 
end;// 

delimiter; 

这里是MySQL测试

mysql> create table person4(id int, name varchar(20),salary int); 
Query OK, 0 rows affected (0.16 sec) 

mysql> insert into person4 values (1,'aa',6000); 
Query OK, 1 row affected (0.06 sec) 
mysql> select * from person4; 
+------+------+--------+ 
| id | name | salary | 
+------+------+--------+ 
| 1 | aa | 6000 | 
+------+------+--------+ 
1 row in set (0.01 sec) 

mysql> insert into person4 values (1,'bb','3000'); 
Query OK, 1 row affected (0.04 sec) 

mysql> select * from person4; 
+------+------+--------+ 
| id | name | salary | 
+------+------+--------+ 
| 1 | aa | 6000 | 
| 1 | bb | 6000 | 
+------+------+--------+ 
2 rows in set (0.00 sec)