任何人都可以解释输出

Question

#define power(a) #a 
    int main() 
    { 
    printf("%d",*power(432)); 
    return 0; 
    } 

任何人都可以解释o/p？
the o/p is

Answer 1

它等效于：

printf("%d",*"432"); 

这相当于：

printf("%d", '4'); 

和'4' ASCII值是52。

Answer 2

#define power(a) #a //# is a stringization operation in macro 
    int main() 
    { 
    printf("%d",*power(432)); 
    return 0; 
    } 

Hence after calling power(432), macro will return it "432" and applying * on it gives first value which is nothing but 52 (48 + 4) for '4' .