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我试图显示一条错误消息,如果我的表单中的选择按钮没有改变。它工作正常,但没有选择,请帮助!我知道图像不会像那样工作,我不能将图像作为新成员发布。表单验证:请选择
HTML是:
<div id='first_name_error' class='error'><image code here></div>
<div><input type='text' name='first_name' id='first_name' placeholder="YOUR FIRST NAME*"></div>
Number of Guests:*<div id='guests_error' class='error'><img src='img/booking/error.png'></div>
<div><select name='guests' id='guests' style="margin:0px;" SIZE="1"><OPTION SELECTED value="guests">Guests<OPTION>2<OPTION>3<OPTION>4</SELECT></div>
代码是你的 “客人” 变量已经被设置为选择元素的值
var error = false;
var first_name = $('#first_name').val();
var second_name = $('#second_name').val();
var email = $('#email').val();
var number = $('#number').val();
var guests = $('#guests').val();
var message = $('#message').val();
if(first_name.length == 0){var error = true;$('#first_name_error').fadeIn(500);}else{$('#first_name_error').fadeOut(500);}
if(guests.value == Guests){var error = true;$('#guests_error').fadeIn(500);}else{$('#guests_error').fadeOut(500);}
你是我的!我希望我能给你买一杯饮料...... – Michael 2012-03-03 19:03:33