AlertDialog.Builder打开另一个AlertDialog.Builder

Question

我想在另一个AlertDialog中打开一个AlertDialog，但它不工作，为什么它不工作的任何想法？

String items[] = {"Details","Edit","Delete"} 
AlertDialog.Builder alert = new AlertDialog.Builder(getAplicationContext()); 
alert.setTitle("Options"); 
alert.setItems(items, new OnClickListener() { 

    public void onClick(DialogInterface dialog, int item) { 
     switch(item){ 
      case 0: 
       AlertDialog.Builder alert2 = new AlertDialog.Builder(getAplicationContext()); 
       alert2.setTitle("Details"); 
       alert2.setMessage(getDetails()); 
       alert2.setNeutralButton("Close", null); 
       alert2.show(); 
      return; 

      case 1: 
       //not important for the question 
      return; 

      case 2: 
       //not important for the question 
      return; 
     } 
    } 
}); 

alert.setNegativeButton("Cancel", null); 
alert.show(); 

Answer 1

该问题可能是您用于AlertDialog的环境。尝试在两者中使用MyActivityName.this，用您的Activity的名称替换MyActivityName。

因此，建设的第一个AlertDialog应该是这样的

AlertDialog.Builder alert = new AlertDialog.Builder(MyActivityName.this);

然后

AlertDialog.Builder alert2 = new AlertDialog.Builder(MyActivityName.this);

的第二个。