如何创建测试执行的日志文件

Question

我想创建一个测试控制器，并希望测试的执行被收集到一个文件。

我知道使用，三通和重定向测试脚本执行到某个文件，但我有兴趣与蟒蛇在linux下做到这一点。

所以，每当执行测试时，应该得到创建的日志文件，所有的执行日志，包括标准输入，输出和错误应该得到收集到这个文件这种情况。

请求某些机构建议我，如何实现这种想法！

感谢 的OpenFile

Answer 1

打开并写入文件：

mylogfile = 'bla.log' 
f = open(mylogfile, 'a') 
f.write('i am logging! logging logging!....loggin? timber!....') 
f.close() 

看在根目录下有脚本 'bla.log' 和读取，享受

Answer 2

您可以编写一个函数像这样：

def writeInLog(msg): 
    with open("log", "a") as f: 
     f.write(msg+"\n") 

它会打开文件“日志“，然后附加（”a“）消息后跟一个换行符，然后关闭该文件。

Answer 3

# Save the current stream 
saveout = sys.stdout 


f = "a_log_file.log" 
fsock = open(f, 'w') 

# Set stream to file 
sys.stdout = fsock 

### 
# do something here 
# any print function will send the stream to file f 
### 

# Reset back the stream to what it was 
sys.stdout = saveout 
fsock.close() 

Answer 4

试试这个：

import sys 

# Save the current stream 
save_out = sys.stdout 

# Define the log file 
f = "a_log_file.log" 
# Append to existing log file. 
# Change 'a' to 'w' to recreate the log file each time. 
fsock = open(f, 'a') 

# Set stream to file 
sys.stdout = fsock 

### 
# do something here 
# any print function calls will send the stream to file f 
### 

# Reset back the stream to what it was 
# any print function calls will send the stream to the previous stream 
sys.stdout = save_out 
fsock.close() 

Answer 5

有几个很好的日志记录模块，从内置的logging，这里是official cookbook。比较有趣的第三方库是Logbook，这里是一个相当裸例子只是皮毛其very cool features的表面：

import logbook 

def f(i,j): 
    return i+j 

logger = logbook.Logger('my application logger') 
log = logbook.FileHandler('so.log') 
log.push_application() 

try: 
    f(1, '2') 
    logger.info('called '+f.__name__) 
except: 
    logger.warn('failed on ') 


try: 
    f(1, 2) 
    logger.info('called '+f.__name__) 
except: 
    logger.warn('choked on, ') 

so.log则是这样的：

[2011-05-19 07:40] WARNING: my application logger: failed on 
[2011-05-19 07:40] INFO: my application logger: called f