gitpython：对于git的命令语法提交

Question

使用gitpython模块，我写python脚本来检查git的差异 - > git的添加所有修改过的文件逐一。最后，我想提交所有这些更改，但是我没有找到命令的确切语法。

我试着用下面的代码，'git add'完美工作，但'git commit'给出错误。

import git 

repo = git.Repo(os.getcwd() 
files = repo.git.diff(None, name_only=True) 
for f in files.split('\n'): 
    show_diff(f) 
    repo.git.add(f) 

repo.git.commit('test commit', author='sunilt@xxx.com') 

这是我看到的错误，它似乎在cmd参数中缺少某些东西。

In [10]: repo.git.commit("test commit", author="sunilt@xxx.com") 
--------------------------------------------------------------------------- 
GitCommandError       Traceback (most recent call last) 
<ipython-input-10-b4505b7c53c2> in <module>() 
----> 1 repo.git.commit("test commit", author="sunil.thorat@nuance.com") 

c:\python27\lib\site-packages\git\cmd.pyc in <lambda>(*args, **kwargs) 
    421   if name[0] == '_': 
    422    return LazyMixin.__getattr__(self, name) 
--> 423   return lambda *args, **kwargs: self._call_process(name, *args, **kwargs) 
    424 
    425  def set_persistent_git_options(self, **kwargs): 

c:\python27\lib\site-packages\git\cmd.pyc in _call_process(self, method, *args, **kwargs) 
    866   call.extend(args) 
    867 
--> 868   return self.execute(call, **_kwargs) 
    869 
    870  def _parse_object_header(self, header_line): 

c:\python27\lib\site-packages\git\cmd.pyc in execute(self, command, istream, with_extended_output, with_exceptions, as_process, output_stream, stdout_as_string, kill_after_timeout, with_stdout, universal_newlines, shell, **subprocess_kwargs) 
    684 
    685   if with_exceptions and status != 0: 
--> 686    raise GitCommandError(command, status, stderr_value, stdout_value) 
    687 
    688   if isinstance(stdout_value, bytes) and stdout_as_string: # could also be output_stream 

GitCommandError: Cmd('git') failed due to: exit code(1) 
    cmdline: git commit --author=sunilt@xxx.com test commit 
    stderr: 'error: pathspec 'test commit' did not match any file(s) known to  git.' 

Answer 1

解决了这个问题，需要在如下commit命令添加 “-m” 标志：

repo.git.commit('-m', 'test commit', author='sunilt@xxx.com')