如何检查阵列的模式？

Question

如何在匹配模式的内容中返回索引数组。

var contents = ["Dog is big","Cat is small","Horse is huge"] 

(contents,"og") //returns [0,2] 
(contents,"at") //returns [1] 
(contents,"..") //etc 

所以，“O”和“G”都在0和2，但不是在1

注：字母不必是按照这个顺序。

Answer 1

使用Array#forEach和Array#every方法。

var contents = ["Dog is big", "Cat is small", "Horse is huge"] 
 

 
console.log(get(contents, "og")); 
 
console.log(get(contents, "at")); 
 
console.log(get(contents, "..")); 
 

 
function get(arr, str) { 
 
    // array for storing result 
 
    var res = []; 
 
    // iterate over string array 
 
    arr.forEach(function(v, i) { 
 
    // split string into individual character and 
 
    // check for each for match 
 
    // if all elements matched push the element 
 
    if (str.split('').every(function(v1) { 
 
     return v.indexOf(v1) > -1; 
 
    })) 
 
     res.push(i); 
 
    }); 
 
    return res; 
 
}

Answer 2

您可以使用Array.prototype.reduce和Array.prototype.every过滤掉其中指数符合您的标准 - 看演示如下：

var contents = ["Dog is big","Cat is small","Horse is huge"]; 
 

 
function filter(filter) { 
 
    var f = filter.split(''); 
 
    return contents.reduce(function(p,c,i){ 
 
    f.every(e=>~c.indexOf(e)) && p.push(i); 
 
    return p; 
 
    },[]); 
 
} 
 

 
console.log(filter("og")); 
 
console.log(filter("at"));