1
我想获取swift类的属性列表。有类似的问题here和here。我有一切工作,除了某些类型不从class_copyPropertyList
返回。到目前为止我测试过的那些是Int?
和枚举。我正在尝试下面的示例类。获取Swift类的属性列表
enum PKApiErrorCode: Int {
case None = 0
case InvalidSignature = 1
case MissingRequired = 2
case NotLoggedIn = 3
case InvalidApiKey = 4
case InvalidLogin = 5
case RegisterFailed = 6
}
class ApiError: Serializable {
let code: PKApiErrorCode?
let message: String?
let userMessage: String?
init(error: JSONDictionary) {
code = error["errorCode"] >>> { (object: JSON) -> PKApiErrorCode? in
if let c = object >>> JSONInt {
return PKApiErrorCode.fromRaw(c)
}
return nil
}
message = error["message"] >>> JSONString
userMessage = error["userMessage"] >>> JSONString
}
}
而且Serializable类(与https://gist.github.com/turowicz/e7746a9c035356f9483d一些帮助是
public class Serializable: NSObject, Printable {
override public var description: String {
return "\(self.toDictionary())"
}
}
extension Serializable {
public func toDictionary() -> NSDictionary {
var aClass : AnyClass? = self.dynamicType
var propertiesCount : CUnsignedInt = 0
let propertiesInAClass : UnsafeMutablePointer<objc_property_t> = class_copyPropertyList(aClass, &propertiesCount)
var propertiesDictionary : NSMutableDictionary = NSMutableDictionary()
for var i = 0; i < Int(propertiesCount); i++ {
var property = propertiesInAClass[i]
var propName = NSString(CString: property_getName(property), encoding: NSUTF8StringEncoding)
var propType = property_getAttributes(property)
var propValue : AnyObject! = self.valueForKey(propName);
if propValue is Serializable {
propertiesDictionary.setValue((propValue as Serializable).toDictionary(), forKey: propName)
} else if propValue is Array<Serializable> {
var subArray = Array<NSDictionary>()
for item in (propValue as Array<Serializable>) {
subArray.append(item.toDictionary())
}
propertiesDictionary.setValue(subArray, forKey: propName)
} else if propValue is NSData {
propertiesDictionary.setValue((propValue as NSData).base64EncodedStringWithOptions(nil), forKey: propName)
} else if propValue is Bool {
propertiesDictionary.setValue((propValue as Bool).boolValue, forKey: propName)
} else if propValue is NSDate {
var date = propValue as NSDate
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "Z"
var dateString = NSString(format: "/Date(%.0f000%@)/", date.timeIntervalSince1970, dateFormatter.stringFromDate(date))
propertiesDictionary.setValue(dateString, forKey: propName)
} else {
propertiesDictionary.setValue(propValue, forKey: propName)
}
}
return propertiesDictionary
}
public func toJSON() -> NSData! {
var dictionary = self.toDictionary()
var err: NSError?
return NSJSONSerialization.dataWithJSONObject(dictionary, options:NSJSONWritingOptions(0), error: &err)
}
public func toJSONString() -> NSString! {
return NSString(data: self.toJSON(), encoding: NSUTF8StringEncoding)
}
}
弦乐似乎如果选配的有效值和code
从来没有在对象上似乎只出现,如果它是一个枚举或诠释,除非诠释有一个默认值。
感谢您的任何意见,我可以得到得到一个类的所有属性,不管它们是什么。
是否有人甚至有线索从哪里开始,或者是否有人需要更多的信息? – smitt04 2014-09-08 14:10:29
我有这个完全相同的问题,使用同样的要点。这是一个月在这个questi上。任何更新?我一直在摇头,认为必须有一种直接的方式来序列化一个快速的课程,但我还没有找到一个端到端的方法。 – 2014-10-15 22:34:46