1
我有一个MySQL表称为用户。行有4个字段,如下所示:从表其中name选择ID =? ...查询失败
INT(10) | serialized php array | CHAR(24) | CHAR(254)
id | profile | name | email
1 | ..ybl4JFtmhQEQVwQOXjo... | TestName | [email protected]
2 | ..hd+F2yZVYPlxmyalrQo... | NameTest | [email protected]
我有一个用户(TestName)的名称并希望获得唯一的用户标识(1)。 为什么下面的代码无法正常工作?
function dataBase() {
$dataBase = @new MySQLi("localhost", "name", "password", "databasename");
if (mysqli_connect_errno()) {
safeExit("Failed to establish connection to MySQL database, error: ".mysqli_connect_error(), 'msgError');
} else {
return $dataBase;
}
}
// connect to database
$db = dataBase();
$sql = 'SELECT
id
FROM
Users
WHERE
name = ?
LIMIT
1';
$stmt = $db->prepare($sql);
if (!$stmt) {
safeExit($db->error, 'msgError');
}
$name = 'TestName';
$stmt->bind_param('s', $name);
if (!$stmt->execute()) {
safeExit($stmt->error, 'msgError');
}
$stmt->bind_result($uid);
$stmt->close();
echo $uid;
该代码输出一个zer0。我可以排除语法错误。查询必须有错误。
感谢。这有帮助。 – u7f1mrfpf 2012-04-01 18:47:41