多少具体的价值在安卓

Question

一个字符串数组存在我有一个字符串数组是这样的：

String[] sample = { "0", "1", "0", "5", "1", "0" }; 

现在我需要知道有多少特定值这样的数组中存在0。 所以我怎么能得到这个？

Answer 1

希望这可以帮助你..

int count = 0; 
    String[] array = new String[]{"a", "a", "d", "c", "d", "c", "v"}; 
    ArrayList<String> arrayList = new ArrayList<String>(Arrays.asList(array)); 
    for (int i = 0; i < array.length; i++) { 
     count = 0; 
     for (int j = 0; j < arrayList.size(); j++) { 
      if (arrayList.get(j).equals(array[i])) { 
       count++; 
      } 
     } 
     System.out.println("Occurance of " + array[i] + " in Array is : " + count); 
    } 

Answer 2

尝试HashMap跟踪数组中每个单词的出现次数。

public static void main(String[] args) { 
     String[] sample = { "0", "1", "0", "5", "1", "0" }; 
     Map<String, Integer> map = new HashMap<>(); 
      for (String s : sample) { 
       Integer n = map.get(s); 
       n = (n == null) ? 1 : ++n; 
       map.put(s,n); 
      } 

      System.out.println(map); 

    } 

输出：（希望这是你想要的）

{1=2, 0=3, 5=1} 

的迭代地图使用：

Iterator it = map.entrySet().iterator(); 
    while (it.hasNext()) { 
     Map.Entry pair = (Map.Entry)it.next(); 
     System.out.println(pair.getKey() + " occurs = " +  pair.getValue()+" times"); 

    } 

输出：

1 occurs = 2 times 
0 occurs = 3 times 
5 occurs = 1 times