我正在努力验证一个复选框,似乎无法理解它出错的地方。任何帮助都会很棒。因为它是以数组形式从MySQL中提取的,所以我不确定这是不是我要出错的地方。Javascript复选框验证不在php中工作
<script language="JavaScript" type="text/javascript">
function checkform (form)
{
if(!form.check_box_delete[].checked) {
alert('Please check at least one of the options.');
return false;
}
return true;
}
</script>
这里是人体代码:
<form name="form" method="post" action="loan_checkedIn.php" onsubmit="return checkform(this);">
<?php
echo "<table border='1' align='center' width='900'>
<tr>
<th bgcolor='#00a3e0'><font face='Arial'>Select</font></th>
<th bgcolor='#00a3e0'><font face='Arial'>Customer</font></th>
<th bgcolor='#00a3e0'><font face='Arial'>Make</font></th>
<th bgcolor='#00a3e0'><font face='Arial'>Model</font></th>
</tr>";
$results = mysql_query("SELECT * FROM loan WHERE email='$email' AND status='Out'");
while($row1 = mysql_fetch_array($results))
{
echo "<tr>";
echo "<td align='center'><input type='checkbox' name='check_box_delete[]' value='" . $row1['id'] . "'></td>";
echo "<td align='center'><font face='Arial'>" . $row1['customer'] . "</font></td>";
echo "<td align='center'><font face='Arial'>" . $row1['make'] . "</font></td>";
echo "<td align='center'><font face='Arial'>" . $row1['model'] . "</font></td>";
echo "</tr>";
}
echo "</table>";
?>
<p align="center"><input type="submit" style="background-color:#00A3E0; color:#FFFFFF;" name="submit" value="Return Equipment"></p>
</form>
第一个问题,你得到的复选框列表? – Ravi
是的,它使用复选框在多行的一侧从MySQL中提取所有细节,如果选中,系统工作正常,但如果没有检查,则说实际上没有检查完成。 – Coops
您应该查看开发人员工具控制台,您将看到语法错误:'form.check_box_delete []'无效js –