无法在下拉框中发布从db中选择的值

Question

我花了一些时间试图让下拉框正常工作，从数据库中获取部门和位置的值。这工作正常，我添加了额外的日期字段，因此客户可以选择特定时期，地点和部门的记录。当我执行运行departmentReport.php的表单时，即使试图回显每个值，页面也会返回空白，如下所示。

<form id="departmentReport" action="departmentReport.php" method="get" onsubmit="#"> 
     <fieldset id="departmentReport"> 
      <h3>Department Report</h3> 
      <br> 
      <?php 
      include 'includes/DbCon.php'; 
     $sql = "select department_name from departments"; 

      echo"<select name = 'departments' value=''>Department Name</option>"; 

      foreach ($conn->query($sql) as $row){ 
       echo "<option value=$row[department_name]>$row[department_name]</option>";} 
      echo "</select>"; 

      ?> 
      <br></br> 
    <?php 
      include 'includes/DbCon.php'; 
     $sql = "select `location_name` from `location`"; 

      echo "<select name = 'location' value=''>Location Name</option>"; 

      foreach ($conn->query($sql) as $row){ 
       echo "<option value=$row[location_name]>$row[location_name]</option>";} 
      echo "</select>"; 

      ?> 
      <br></br><br> 
       <label for="date">Date From<br></label> 
       <input id="date1" type="date" name="dateF" 
         autofocus="true"/> 
      <br> 
      <br> 
       <label for="date">Date To<br></label> 
       <input id="date2" type="date" name="date2" 
         autofocus="true"/> 
      <br> 
      <br> 
      <input type="submit" class="button" value="Submit"> 

在提交departmentReport.php被付诸行动

<?php 


include "../includes/dbCon.php"; //* CONNECTION TO DATABASE 

$department = mysqli_real_escape_string($conn, $_POST['departments']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$location = mysqli_real_escape_string($conn, $_POST['location']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$date1 = mysqli_real_escape_string($conn, $_POST['date1']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 
$date2 = mysqli_real_escape_string($conn, $_POST['date2']); //* CLEAN DATA, THIS DELETES ANY SPECIAL CHARACTERS THAT CAN BE USED FOR MALICIOUS CODE 

echo "$department"; 
echo "$location"; 
echo "$date1"; 
echo "$date2"; 

这带来下面的结果..

但是调整后什么时候能得到我见我选择的值为 http://localhost:8888/departmentReport.php?departments=Marketing&location=London&dateFrom=02%2F01%2F2017

我不确定为什么我看不到值时回声！

任何援助将不胜感激。

Answer 1

您检索发布数据时，变量是错误的

选择部门的html代码：

<select name = departments value=''>Department Name</option> 

在选择的形式，名称是“部门”，但是当你在PHP中检索它们，它是：

$_POST['departmant_name'] 

这是错误的输入变量名称。它应该是：

$_POST['departments'] 

另外，请把报价上的选择名称

<select name = 'departments' value=''>Department Name</option> 

所有其他变量也是错误的标记。

看起来像你输入数据库列名称，而不是表单输入名称。

编辑： 我也注意到，在您的表单，表单“方法”设置为“GET”，而你的PHP代码是使用“POST”