iTunes搜索商店api

Question

我想从API iTunes Store获取数据到我的PHP文件。在搜索表单中，您可以填写歌曲的艺术家和标题。我只想显示歌曲中的数据。这是我的代码：

$title = $_POST["title"]; 
$artist = $_POST["artist"]; 
$query_string = urlencode($title); 
$query_string2 = urlencode($artist); 
$json = file_get_contents('https://itunes.apple.com/search?term=$query_string&term=$query_string2'); // this WILL do an http request for you 
$data = json_decode($json); 

echo "<div class='container' id='movies'>"; 
echo "<div class='col-md-4' id='movie'>"; 
echo "<img src='" .$data->artworkUrl60. "' width='200'>"; 
echo "<h4>" .$data->artistName. " - " .$data->trackName. "</h4>"; 

我得到这个错误：注意：未定义的属性：stdClass的:: $ artworkUrl60中.... 请告诉我错我的代码？

Answer 1

因为您的$ data对象不包含名为$ artworkUrl60的属性。 您的HTTP查询无法正常工作，您应该使用双引号而不是单引号。

// For limit you can add 'limit' parameter 
$json = file_get_contents("https://itunes.apple.com/search?term=$query_string&term=$query_string2&limit=20"); 
// OR concatenation 
// $json = file_get_contents('https://itunes.apple.com/search?term='.$query_string.'&term='.$query_string2); 
$data = json_decode($json); 

if (0 == $data->resultCount) { 
    echo 'No result found ! '; 
} 
else { 
    foreach ($data->results as $row){ 
     echo "<div class='container' id='movies'>"; 
     echo "<div class='col-md-4' id='movie'>"; 
     echo "<img src='" .$row->artworkUrl60. "' width='200'>"; 
     echo "<h4>" .$row->artistName. " - " .$row->trackName. "</h4>"; 
    } 
} 

https://affiliate.itunes.apple.com/resources/documentation/itunes-store-web-service-search-api/#searchexamples