的JavaScript以特定方式

我有坐标的下方阵列组织阵列：的JavaScript以特定方式

var coords = [35.77204705542798, -5.815865197320899, 35.77205120747819, -5.815754188240848, 35.77197468036722, -5.815810097181759, 35.77201185726312, -5.816182008817898, 35.77188028308802, -5.816782866625928, 35.77144809183601, -5.817054836919457, 35.77130127311978, -5.817231221149015, 35.77121654704168, -5.817323279458099, 35.77197602552531, -5.818491135420929, 35.77211527443405, -5.818831898394636, 35.77220613582161, -5.819054426882189, 35.77225761824354, -5.819182167400329, 35.77557809840525, -5.819685065789988, 35.77522352494348, -5.821346612263469, 35.77815743782872, -5.822735160242799, 35.77863231735067, -5.822959942846667, 35.77915215012052, -5.823206036666789, 35.77917987363854, -5.82321907562955, 35.77913908191616, -5.825751400638378, 35.77947725976961, -5.826044519616627, 35.77923063670355, -5.82893344672563, 35.77920722271806, -5.829544463218058, 35.77924325929096, -5.82965650991142, 35.77913169320556, -5.830906964998152, 35.77917349450947, -5.830173084585434, 35.78563643141488, -5.829373128632887, 35.7859055726137, -5.829317961099034, 35.78659089504106, -5.829249272155759, 35.78704770052305, -5.829163948962961, 35.78696081760869, -5.829114610331397, 35.78687737614365, -5.829067226012621, 35.78679073445069, -5.829018024365507, 35.78661289235281, -5.828929232334034, 35.78652027010703, -5.828884857172518, 35.78643576729606, -5.828844387274908, 35.78635159916791, -5.828804167105649, 35.7862672257822, -5.828763857888811, 35.7872100444153, -5.866787159467321]

基本上，顺序是像下面([lat,lng,lat,lng........])

var waypts = []; 

//should execute for loop here, get lat and lng from the array 
stop = new google.maps.LatLng(lat, lng) 
waypts.push({ 
    location: stop, 
    stopover: true 
}); 
///

我试过以下，但它似乎只运行一次

for(var i=0; i<=coords.length; i++){ 
//get only even so I can have something like coords.slice(0,2), coords.slice(2,4) 
if ((i % 2) == 0){ 
coords.slice(i+0,i+2) 
} 
}

将在后台运行的最终结果应该是si milar到：

stop = new google.maps.LatLng(35.77205120747819, -5.815754188240848) 
waypts.push({ 
    location: stop, 
    stopover: true 
}); 

stop = new google.maps.LatLng(35.77197468036722, -5.815810097181759) 
waypts.push({ 
    location: stop, 
    stopover: true 
});

来源

2017-06-13 Folky.H

@Santi我已为所需的输出 –

你可以只遍历每个对：

for(var i=1; i<coords.length; i+=2){ 
    var lat=coords[i-1],long=coords[i]; 

stop = new google.maps.LatLng(lat, lng) 
}

来源

2017-06-13 19:39:47

不需要做模块化数学 - 只需使用i和++i（这将增加i循环将正常处理）

for(var i=0; i<=coords.length; i += 2) { 
    if ((i + 1) <= coords.length) { 
     waypts.push({ 
      location: new google.maps.LatLng(coords[i], coords[i + 1]), 
      stopover: true 
     }); 
    } 
}

来源

2017-06-13 19:40:12 tymeJV

这将是一个更清洁的方式做'我+ = 2'在环头，只是'我在机身+ 1'。突变体内的循环变量是一个很大的禁忌。 – georg

@georg - 是的，我在想 - 我相信迟早会导致头痛。我根据您的建议编辑了答案 - 感谢您的意见！ – tymeJV

看看这个工作例子，我减少了坐标的数目更具可读性。

var coords = [35.77204705542798, -5.815865197320899, 35.77205120747819, -5.815754188240848, 35.77197468036722, -5.815810097181759]; 
 

 
for (var i = 0; i <= coords.length - 2; i++) { 
 
    if ((i % 2) == 0) { 
 
    console.log("Lat:" + coords[i]); 
 
    console.log("Lon:" + coords[i + 1]); 
 
    /*stop = new google.maps.LatLng(coords[i], coords[i + 1]) 
 
    waypts.push({ 
 
     location: stop, 
 
     stopover: true 
 
    });*/ 
 
    } 
 
}

来源

2017-06-13 19:43:17

您可以在COORDS阵列转换成对象的阵列，每一个都包括lat和长变量。我为每个经纬度使用不同的值，以使其不会太长。

var coords = [{lat:1,long:2},{lat:3,long:4},{lat:5,long:6},{lat:7,long:8}]; 
for(var i=0; i<=coords.length; i++) { 
    // perform rest of operation here 
}

来源

2017-06-13 19:49:36 hRdCoder

您可以使用while和shift还是比较干净的。

while(coords.length) stop = new google.maps.LatLng(coords.shift(), coords.shift());

来源

2017-06-13 19:50:30

coords.length> = 2会是更好的条件... –

的JavaScript以特定方式

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