反序列化时丢失对象

Question

我有一个奇怪的问题，很困惑。我想通过电线发送数据集并对其进行序列化。当我反序列化时，我想检索对象和它的属性。但是，当我DESERIALIZE（EDITED）时，它似乎失去了与基类相关的子类。我创建了以下类：

[Serializable] 
    public class DataAttributeColumn : DataColumn, ISerializable 
    { 

     private string attributeName; 

     [DataMember(IsRequired = true)] 
     public string AttributeName 
     { 
      get { return attributeName; } 
      set { attributeName = value; } 
     } 

     public void GetObjectData(SerializationInfo info, StreamingContext context) 
     { 
      info.AddValue("AttributeName", this.AttributeName); 
     } 
    } 

而不是使用列名的DataColumn的，我想扩展它的添加属性名称。这一切都工作100％，直到我通过电线发送。

我创建了以下Test类并使用了Binary和DataContract序列化程序。

public class Test 
    { 
     DataSet ds = new DataSet(); 
     DataTable dt = new DataTable(); 
     DataAttributeColumn dac = new DataAttributeColumn(); 

     public void CreateData() 
     { 
      ds.Tables.Add(dt); 
      dac.AttributeName = "MyAttribute"; 
      dt.Columns.Add(dac); 

     } 

     public void SerializeBinary() 
     { 
      DataSet dss = new DataSet(); 

      BinaryFormatter dcs = new BinaryFormatter(); 
      ds.RemotingFormat = SerializationFormat.Xml; 

      string strTempfilePath = "binary.txt"; 
      FileStream fs; 
      using (fs = new FileStream(strTempfilePath, FileMode.OpenOrCreate, FileAccess.ReadWrite)) 
      { 
       dcs.Serialize(fs, ds); 
      } 

      fs = new FileStream(strTempfilePath, FileMode.Open); 
      dss = dcs.Deserialize(fs) as DataSet; 

      DataAttributeColumn dac2 = null; 
      dac2 = dss.Tables[0].Columns[0] as DataAttributeColumn; 

      if (dac2 != null) 
      { 
       Console.WriteLine("YOU DID IT!!!!"); 
      } 
      //Second Serialize 
      using (fs = new FileStream("binary2.txt", FileMode.OpenOrCreate, FileAccess.ReadWrite)) 
      { 
       dcs.Serialize(fs, dss); 
      } 
     } 
     public void SerializeDataContract() 
     { 
      DataSet dss = new DataSet(); 

      Type[] knowntypes = { typeof(DataAttributeColumn), typeof(DataColumn) }; 
      DataContractSerializer dcs = new DataContractSerializer(typeof(DataSet), knowntypes); 
      MemoryStream stream = new MemoryStream(); 
      ds.RemotingFormat = SerializationFormat.Xml; 

      string strTempfilePath = "datacontract.txt"; 
      FileStream fs; 
      using (fs = new FileStream(strTempfilePath, FileMode.OpenOrCreate, FileAccess.ReadWrite)) 
      { 
       dcs.WriteObject(fs, ds); 
      } 

      fs = new FileStream(strTempfilePath, FileMode.Open); 
      dss = dcs.ReadObject(fs) as DataSet; 

      DataAttributeColumn dac2 = null; 
      dac2 = dss.Tables[0].Columns[0] as DataAttributeColumn; 
      if (dac2 != null) 
      { 
       Console.WriteLine("YOU DID IT!!!!"); 
      } 

      using (fs = new FileStream("datacontract2.txt", FileMode.OpenOrCreate, FileAccess.ReadWrite)) 
      { 
       dcs.WriteObject(fs, dss); 
      } 
     } 
    } 

我的目标是创建一个属性，当我反序列化，我可以从DataColumn中投的对象放回DataAttributeColumn，以获取“的AttributeName”。

我该怎么做到这一点？

编辑：反序列化后serializatiion

<DataSet><xs:schema id="NewDataSet" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"><xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true"><xs:complexType><xs:choice minOccurs="0" maxOccurs="unbounded"><xs:element name="Table1"><xs:complexType><xs:sequence><xs:element name="Column1" msdata:**AttributeName="MyAttribute"** type="xs:string" minOccurs="0"/></xs:sequence></xs:complexType></xs:element></xs:choice></xs:complexType></xs:element></xs:schema><diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"/></DataSet> 

和输出后的输出：

<DataSet><xs:schema id="NewDataSet" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"><xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true"><xs:complexType><xs:choice minOccurs="0" maxOccurs="unbounded"><xs:element name="Table1"><xs:complexType><xs:sequence><xs:element name="Column1" type="xs:string" minOccurs="0"/></xs:sequence></xs:complexType></xs:element></xs:choice></xs:complexType></xs:element></xs:schema><diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"/></DataSet> 

Answer 1

的关键是以下行：

Type[] knowntypes = { typeof(DataAttributeColumn), typeof(DataColumn) }; 

你需要使用这些knowntypes每个Serialize或Deserialize每次。这样格式化程序就会知道保存一个合适的实际类，即使包含它的数组是用子类声明的。检查你自己的代码，你在一个地方正确使用它，而不是在其他地方使用它！

Answer 2

让我们尝试一种不同的方法。使用XmlSerializer的：

 XmlSerializer serializer = new XmlSerializer(typeof(DataSet)); 
     FileStream fs = new FileStream(yourFilePath, FileMode.Create); 
     XmlWriterSettings Settings = new XmlWriterSettings(); //Please use this! 
     Settings.Indent = true; 
     Settings.IndentChars = " "; 
     Settings.NewLineHandling = NewLineHandling.None; 
     Settings.NewLineChars = "\n"; 
     XmlWriter writer = XmlWriter.Create(fs, Settings); 
     //XmlWriter writer = new XmlTextWriter(fs, Encoding.ASCII); 
     serializer.Serialize(writer, ds); 
     writer.Close(); 
     fs.Close(); 

反序列化使用：

 XmlReader reader = new XmlTextReader(fs); 
     DataSet ds2 = (DataSet)serializer.Deserialize(reader); 
     reader.Close();