2016-09-27 118 views
1

我想创建应用程序,可以从端口接收SMS!但是运行它时,我的msg.getMessageBody()返回null。我该如何解决它?从端口接收短信

manifext.xml

<receiver android:name="data.SMSReceiver" android:enabled="true"> 
     <intent-filter> 
      <action android:name="android.provider.telephony.SMS_RECEIVED" /> 
      <data android:scheme="sms" 
       android:host="*" 
       android:port="4030"/> 
     </intent-filter> 

广播接收机代码

public class SMSReceiver extends BroadcastReceiver { 

private static final String SHORTCODE = "+9810004473"; 

@Override 
public void onReceive(Context context, Intent intent) { 
    Bundle bundle = intent.getExtras(); 

    Object[] messages = (Object[])bundle.get("pdus"); 
    SmsMessage[] sms = new SmsMessage[messages.length]; 
    for(int n=0; n < messages.length; n++) { 
     sms[n] = SmsMessage.createFromPdu((byte[]) messages[n]); 
    } 
    for(SmsMessage msg : sms) { 
     if(TextUtils.equals(msg.getOriginatingAddress(), SHORTCODE)) { 
      Toast.makeText(context, "SMS: " + msg.getMessageBody(), Toast.LENGTH_LONG).show(); 
     } 
    } 
} 

}

Toast显示:SMS: null

+1

数据短消息中不会有消息正文。使用'SmsMessage#getUserData()'方法检索数据,数据将采用'byte'数组的形式,如上面链接文章的接受答案中所示。 –

+0

tnx!那就对了! –

回答

0

可以在onReceive替换此代码代码:

// Get the object of SmsManager 
final SmsManager sms = SmsManager.getDefault(); 

public void onReceive(Context context, Intent intent) { 

    // Retrieves a map of extended data from the intent. 
    final Bundle bundle = intent.getExtras(); 

    try { 

     Bundle bundle = intent.getExtras(); 

     String recMsgString = "";    
     String fromAddress = ""; 
     SmsMessage recMsg = null; 
     byte[] data = null; 
     if (bundle != null) 
     { 
      //---retrieve the SMS message received--- 
      Object[] pdus = (Object[]) bundle.get("pdus"); 
      for (int i=0; i<pdus.length; i++){ 
       recMsg = SmsMessage.createFromPdu((byte[])pdus[i]); 

       try { 
        data = recMsg.getUserData(); 
       } catch (Exception e){ 

       } 
       if (data!=null){ 
        for(int index=0; index<data.length; ++index) 
        { 
          recMsgString += Character.toString((char)data[index]); 
        } 
       } 

       fromAddress = recMsg.getOriginatingAddress(); 
      } 

    } catch (Exception e) { 
     Log.e("SmsReceiver", "Exception smsReceiver" +e); 

    } 
}  

OK,如果你已编码的邮件前,你想现在你必须遵循自爆措施来对其进行解码,但如果不只是删除您的整个onReceive并替换我的代码。 你在错误的地方解密你的消息,你必须遵循我写的确切步骤。你必须在这里得到的消息(得到data后):

if (data!=null){ 
        for(int index=0; index<data.length; ++index) 
        { 
          recMsgString += Character.toString((char)data[index]); 
        } 
       } 
String decryptedData = Base64.decode(recMsgString ,...)//add this line 

和获取消息字符串recMsgString后,您可以使用Base64类解密。

+1

不!在你的代码中,消息是空的! :( –

+0

TNX Milad!现在,我可以从data = recMsg.getUserData()获取字节数组,但recMsgString具有Byte Format!和新的String(数据,“UTF-8”)不起作用:| –

+0

recMsgString被定义为(int index = 0; index