当我运行这段代码,始终显示在网页“结果错误”或“没有数据即时拍摄”知道我添加在数据库中的数据:其中是错误的始终显示“结果错误”
<?php
if(isset($_POST['update']))
{
$data = getpost();
$search_Query = "SELECT * FROM employee WHERE user_id_assets = $data[0]";
$search_result = mysqli_query($conn , $search_Query);
if($search_result)
{
if(mysqli_num_rows($search_result))
{
while ($row = mysqli_fetch_array($search_result)) {
$user_id_assets = $row['user_id_assets'];
$name_emp = $row['name_emp'];
$user_account = $row['user_account'];
$mail_account = $row['mail_account'];
}
}else{
echo "no Data For This User ID";
}
}else {
echo "result Error";
}
} ?>
从这段代码可以看出'$ conn'从来没有定义过? –
似乎这个'$ data [0]'是空的/ null –
$ conn mighat已经在连接文件中定义了,代码是不完整的... –