IK这是一个愚蠢的,但我无法找到任何解决方案,我的代码是这样的,无论我添加/更改什么代码,它只是不会budge ...(注意即时通讯不使用普通的PHP,使用朋友的版本,是的,是好的,花花公子)无法修改标题信息错误?
<?php
include($_SERVER['DOCUMENT_ROOT'].'/phpAlphaDB/core.php');
?>
<html>
<head>
<link rel="icon" type="image/png" href="../logo.png">
<title> Xenoz Web - Users </title>
<link rel="stylesheet" type="text/css" href="../css/style.php" />
<meta http-equiv="content-type" content="text/html; charset=utf-8">
</head>
<?php
if ($role==0) {
header('Location: http://xenozweb.tk/index.php');
} else {
echo '<script>alert("Hello, '.$username.'. Welcome to the userlist...");</script>';
}
?>
<body>
<div class="navigation">
<a href="index.php"><div class="navitem"> Home </div></a>
<a href="/register/"><div class="navitem"> Register </div></a>
<a href="/login/"><div class="navitem"> Login </div></a>
<a href="https://stackoverflow.com/users/"><div class="navitem"> Users </div></a>
<a href="/jukebox/"><div class="navitem"> Jukebox </div></a>
</div>
</div>
<div class="pagecontent">
<div class="userblock">
<?php
$results = db_read('xenozweb-users', '', 'username');
foreach ($results as $result) {
$u_name = db_column($result, 0);
echo '<div class="users">',$u_name,'</div>';
}
?>
</div>
</div>
</body>
</html>
在[PHP:header](https://secure.php.net/manual/en/function.header.php)中列出的标题之前不会出现任何输出 – FD3