更新查询不起作用。此查询不起作用。更新查询在我的代码中不起作用
我试图打印变量和所有变量包含值
我怎么能解决这个问题?
表单代码:
echo"<td data-title='Status'>";
if ($percent == 0) {
echo"<form class='form-inline' role='form' action='";
?><?php $_PHP_SELF ?><?php
echo"' method='post' accept-charset='UTF-8'>
<select id='' name='status' class='form-control input-md'>
<option valur='.$status.'>$status</option>
<option value='Pending'>Pending</option>
<option value='Cancel'>Cancel</option>
</select>";
echo"</td>";
echo"<input type='hidden' name='txt_id' value='.$id.'>";
echo"<td>";
echo"<input type='submit' name='update' class='btn btn-default' value='Update' />";
}
else if ($percent >= 1 && $percent < 100) {
echo"Running";
}
else if ($percent == 100) {
echo"Done";
}
echo"</td>";
echo"</form>";
更新代码:
if (isset($_POST['update'])) {
$status = $_POST['status'];
$ids = $_POST['txt_id'];
$sql = mysqli_query($conn, "UPDATE tbl_project SET db_status='$status' WHERE db_id='$ids'")or die(mysqli_error($conn));
}
显示你的错误。 –
指定你的错误 – ayush
什么是错误? – BeetleJuice