2016-11-16 66 views
1

我不是一个很棒的编剧,我迷失在翻译中......也许我在做这个完全错误的...Powershell - 让用户从1月到12月的列表中选择

我是建立一个脚本,我希望用户从选择列表中选择,特别是一年的月份。此结果稍后将在脚本中使用。

这里的片段:

$optionQuit = New-Object System.Management.Automation.Host.ChoiceDescription "Quit", "Quit" 
$option1 = New-Object System.Management.Automation.Host.ChoiceDescription "01-January", "01-January OU" 
$option2 = New-Object System.Management.Automation.Host.ChoiceDescription "02-February", "02-February OU" 
$option3 = New-Object System.Management.Automation.Host.ChoiceDescription "03-March", "03-March OU" 
$option4 = New-Object System.Management.Automation.Host.ChoiceDescription "04-April", "04-April OU" 
$option5 = New-Object System.Management.Automation.Host.ChoiceDescription "05-May", "05-May OU" 
$option6 = New-Object System.Management.Automation.Host.ChoiceDescription "06-June", "06-June OU" 
$option7 = New-Object System.Management.Automation.Host.ChoiceDescription "07-July", "07-July OU" 
$option8 = New-Object System.Management.Automation.Host.ChoiceDescription "08-August", "08-August OU" 
$option9 = New-Object System.Management.Automation.Host.ChoiceDescription "09-September", "09-September OU" 
$option10 = New-Object System.Management.Automation.Host.ChoiceDescription "10-October", "10-October OU" 
$option11 = New-Object System.Management.Automation.Host.ChoiceDescription "11-November", "11-November OU" 
$option12 = New-Object System.Management.Automation.Host.ChoiceDescription "12-December", "12-December OU" 
$options = [System.Management.Automation.Host.ChoiceDescription[]]($optionQuit, $option1, $option2, $option3, $option4. $option5, $option6, $option7, $option8, $option9, $option10, $option11, $option12) 
$result = $host.ui.PromptForChoice($title, $message, $options, [int[]](0)) 

不过,我不断收到一个错误:

ERROR: Exception calling "PromptForChoice" with "4" argument(s): "Object reference not set to an instance of an object." TestingMenu.ps1 (31, 1): ERROR: At Line: 31 char: 1 ERROR: + $result = $host.ui.PromptForChoice($title, $message, $options, [int[] ... ERROR: + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ERROR: + CategoryInfo : NotSpecified: (:) [], MethodInvocationException ERROR: + FullyQualifiedErrorId : NullReferenceException ERROR:

我不知道我错过了什么......,我可能使这比需要更复杂...但最终变量$结果应该是像“04年4月”例如。

任何想法我在这里失踪?

+0

你应该发送'Collection',而不是一个数组。你的'ChoiceDescription []'是一个数组。看看MSDN上的例子[这里](https://msdn.microsoft.com/en-us/library/system.management.automation.host.pshostuserinterface.promptforchoice(v = vs.85).aspx) – gravity

+1

有了这么多的选择,你可能会考虑重构你的代码,使之类似于: $ result = $ options | Out-GridView -Title“选择一个项目”-OutputMode Single “可为您提供所需的行为。 –

+1

@gravity由于'Collection'具有[this构造函数](https://msdn.microsoft.com/en-us/library/ms132401.aspx)和单维基于零的数组,因此可以隐式地将数组转换为'Collection'实现'IList'的通用版本。 – PetSerAl

回答

2

看看你的选项变量,你有一个句点,而不是$ option4之后的逗号。

解决这个问题,它应该工作。

$options = [System.Management.Automation.Host.ChoiceDescription[]]($optionQuit, $option1, $option2, $option3, $option4, $option5, $option6, $option7, $option8, $option9, $option10, $option11, $option12) 
+0

grrr ...我不能相信我错过了...谢谢。 – TheCleaner

1

该变体的工作原理并不是多余的。无标记字母与符号&选择,选择是没有意义的

# C:\Test\Choose-CUI.ps1 
[email protected](
    ("&Quit","Quit"), 
    ("0&1-January","01-January OU"), 
    ("0&2-February","02-February OU"), 
    ("0&3-March","03-March OU"), 
    ("0&4-April","04-April OU"), 
    ("0&5-May","05-May OU"), 
    ("0&6-June","06-June OU"), 
    ("0&7-July","07-July OU"), 
    ("0&8-August","08-August OU"), 
    ("0&9-September","09-September OU"), 
    ("1&0-October","10-October OU"), 
    ("11-&November","11-November OU"), 
    ("12-&December","12-December OU") 
) 
$choicedesc = New-Object System.Collections.ObjectModel.Collection[System.Management.Automation.Host.ChoiceDescription] 
for($i=0; $i -lt $choices.length; $i++){ 
    $choicedesc.Add((New-Object System.Management.Automation.Host.ChoiceDescription $choices[$i])) } 
$Host.ui.PromptForChoice($caption, $message, $choicedesc, $default) 

有这个输出

PS C:\Test> .\Choose-CUI.ps1 
[Q] Quit 
[1] 01-January 
[2] 02-February 
[3] 03-March 
[4] 04-April 
[5] 05-May 
[6] 06-June 
[7] 07-July 

[8] 08-August 
[9] 09-September 
[0] 10-October 
[N] 11-November 
[D] 12-December 
[?] Help 
Choice[0]: 
+0

顺便说一句,你可以用'$ choices [$ i]'替换'$ choices [$ i] [0],$ choices [$ i] [1]''。 – PetSerAl

+0

@PetSerAl对不起,它会输出[0]和[1] – LotPings

+0

你试过了吗?因为,我刚才试了一下,发现行为没有什么区别,就像我预料的那样。在你的代码中'$ choices [$ i]'已经是包含两个元素的数组了。当你可以使用原始数组时,没有理由单独获取这些元素并从它们中创建新的数组。 – PetSerAl